Rock's Max Horizontal Distance from Volcano: 500m

AI Thread Summary
A 500m high volcano ejects rocks at a speed of 30 m/s, and the discussion revolves around calculating the maximum horizontal distance the rocks can travel. The initial assumption used the range formula without considering the volcano's height, leading to an incorrect answer of 91.7 m. Participants suggest incorporating the height into the calculations using the equation y = yo + v*t - 0.5*g*t^2, where v is the vertical component of the initial velocity. The correct approach involves relating the height to the time of flight and horizontal distance. This highlights the importance of accounting for both initial velocity and elevation in projectile motion problems.
peace1709
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A 500m high volcano eject rocks at a speed 30 m/s.What is max horizontal distance reached by the rock?
 
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Hi peace1709, Welcome to PF.
What do you about the problem?
In what direction the rocks are moving?
which are the relevant equations?
 
i use the equation range= [(V initial)^2 x (sin 2A)]/[g].
where v inital is 30 m/s and i assume A=45 degrees, and g=9.8 m/s^2
but i got the answer wrong.
 
i got 91.7 m and its wrong, can u help me?
 
In your calculation you have not taken into account the height of the volcano.
 
oh ya.but i don't know how to relate the height. can u help me?
 
You can use the formula
y = yo + v*t - 0.5*g*t^2.
Here v = vo*sinθ
And t = x/vo*cosθ
y is the final position of the rock and yo is the initial position of the rock.
 
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