Volume of the region between two parabolas?

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Homework Statement



Find the volume of the region enclosed by z = 1 - y^2 and z = y^2 - 1 for x lying between 0 and 2 inclusive.

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The Attempt at a Solution



I know that the y bounds are from -1 to 1, where the parabolas meet. x bounds are from 0 to 2. So would the integral simply by the double integral , x from 0 to 2, y from -1 to 1 of the (y^2 -1) - (1 - y^2)? I'm confused at this point. All the limits of integration are constant..
 
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Ah no worries, found out how to solve it! I expressed the x coordinate as f(y,z)=2. Then integrated this function with respect to y and z, with the bounds I specified. Thanks!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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