Volume of the solid using a cylindrical cross section

Neutrinogun
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[STRIKE][/STRIKE]

Homework Statement


Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.


Homework Equations



y = \sqrt{x-1} , y = 0, x = 5; about y = 3


The Attempt at a Solution


I already completed graphing it, but not really sure how to show that here.

2\pi\int_0^2(shell radius)(shell height) dy
2\pi\int_0^2(y)(y^2+1) dy
2\pi\int_0^2(y^3+y) dy
2\pi (((y^4)\div4)) + (y^2)\div2)
2\pi(4+2) - 0
12\pi

Is that correct? I'm not sure if I did the shell height correctly.
 
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You are rotating around y= 3 which means that the axis of each cylinder is y= 3 and the radius is 3- y, not y.
 
Aha, thank you so much! :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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