The discussion focuses on calculating the volume of a solid with isosceles right triangle cross sections defined by the curve y = √x, bounded between x = 0 and x = 9. To find the volume, one must recognize that the area of each triangular cross section is (1/2)(√x)(√x) = x/2. The volume of each infinitesimal slab is then expressed as (x/2)dx, and the total volume can be determined by integrating this expression over the specified boundaries.
PREREQUISITESStudents in calculus, geometry enthusiasts, and anyone involved in mathematical modeling of solids with known cross sections.
enn said:I'm trying to get started on this project but am totally confused about how to find the volume of the solid. All the information I was given was the following:
y= √x
boundaries: 0,9
cross sections: isosceles right triangle
how the hell do I get started?!
You are doing just about everything wrong here. First, you are being rude- not a good way to ask for help. Second, I don't believe this was "all the information" you were given! For example, I'll bet you were told what "y= √x" means and you don't tell us that. I suspect you were told that the right angle of that "iososceles right triangle" lies on the the x-axis and another vertex on the graph of y= √x. Also, I'll bet that you were NOT told "boundaries: 0, 9" but were told that one end of the solid is at x= 0 and the other at x= 9.enn said:I'm trying to get started on this project but am totally confused about how to find the volume of the solid. All the information I was given was the following:
y= √x
boundaries: 0,9
cross sections: isosceles right triangle
how the hell do I get started?!