(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

find the volume of the solid whose base is the region bounded by y^2=9x and x=1 in the xy-plane. each cross section perpendicular to the x-axis is an isosceles right triangle with its hypotenuse in the xy-plane.

2. Relevant equations

[tex]V=\int_{a}^{b}A(x)dx[/tex]

3. The attempt at a solution

well first i solved for y and got y=3sqrt(x) and y=-3sqrt(x), then i figured out the length of the hypotenuse to be 3sqrt(x)-(-3sqrt(x))=6sqrt(x)

but the formula for the area of an isosceles right triangle is 1/2a^2 where a is one of the triangles legs. how do i figure out the length of one of the legs?

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# Finding volume using cross sections

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