VSEPR Theory: Investigating Ionic Molecules

AI Thread Summary
BeF2 is analyzed using VSEPR theory, which indicates that its linear shape results in a net dipole moment of zero, meaning it is nonpolar despite having polar bonds. The discussion clarifies that ionic bonds can exhibit polar characteristics, but the overall polarity of a molecule depends on its geometry and bond orientation. The concept of ionic character versus covalent character is highlighted, emphasizing that substances can possess varying degrees of each. To determine whether a substance is more ionic or covalent, one can calculate its percentage ionic character based on dipole moments. Understanding these principles helps clarify the behavior of ionic molecules within the framework of VSEPR theory.
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Vsepr Theory

Hey Guys! How are u guys doing today?

I was wondering how do we know dat BeF2 is polar?..i drew it out by using the VSEPR theory..but what confuses me is dat BeF2 ionic..can we still use VSEPR theory to draw it out?

Tanya

Thank you in advance! :smile:
 
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Oh Silly me! Ionic bonds are polar bonds.. opps!
 
Strictly speaking, there is nothing that is "ionic". Its a tradeoff between the ionic character and the covalent character that a molecule has. Something that is largely covalent (such as water for example) is usually passed off as a covalent compound as it predominantly behaves so.

Your question was, how do we know that berrylium fluoride is polar. Well, from the VSEPR theory, BeF2 turns out to be linear and it cannot be polar. There are of course bond dipoles but they are oriented antiparallel to each other which makes the net dipole moment of the molecule zero.

If you were asked to find out whether a given substance is covalent or ionic, you would (in theory) calculate its percentage ionic character from a knowledge of the measured dipole moment and the dipole moment for 100% ionic character. This would tell you to what degree is the substance ionic (or covalent).
 
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