Water equivalent of calorimeter

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SUMMARY

The discussion centers on calculating the water equivalent of a calorimeter with a mass of 0.3 kg and a specific heat of 0.2. The equation used is q=cmT, where participants attempted to equate the heat transfer between the calorimeter and water. The correct calculation yields a water equivalent of 0.014 kg, but confusion arises due to the misinterpretation of specific heat and specific gravity, leading to an incorrect expected answer of 0.06 kg. Participants confirm that cancelling out temperature (T) is valid in this context.

PREREQUISITES
  • Understanding of calorimetry principles
  • Familiarity with specific heat and specific gravity concepts
  • Basic algebra for solving equations
  • Knowledge of heat transfer equations, specifically q=cmT
NEXT STEPS
  • Study the concept of water equivalent in calorimetry
  • Learn about specific heat and specific gravity differences
  • Practice solving calorimetry problems using q=cmT
  • Explore common pitfalls in physics problem statements
USEFUL FOR

Students studying thermodynamics, physics educators, and anyone involved in calorimetry and heat transfer calculations.

rasen58
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Homework Statement


The water equivalent in kg, of a calorimeter having a mass of 0.3 kg and a specific heat of 0.2 is

Homework Equations


q=cmT

The Attempt at a Solution


I wanted to set cmT = cmT for the water and calorimeter, but I don't know what the equilibrium temperature is.
So what do I do?
 
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rasen58 said:
I wanted to set cmT = cmT for the water and calorimeter
That's good. Simplify what you set up, and you're in business.
 
Can I cancel out the T's then?
In that case, I would have c1m1 = c2m2
(0.2)(0.3) = (4.186)m2
m2 = 0.014 kg

But the answer says it's 0.06 kg
 
rasen58 said:
Can I cancel out the T's then?
Yes.
rasen58 said:
But the answer says it's 0.06 kg
You have met one of many sloppily stated questions you'll run into in your life. "Specific heat" has been conflated with "Specific gravity." Since water has a specific gravity of "One," the author of the question has chosen "One" as the specific heat for water as well. In kcal/kg, yes, but there is no specification of units in the problem statement.

Your understanding is correct, and your application of that understanding is correct.
 

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