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Water melting

  1. Jun 9, 2009 #1
    1. The problem statement, all variables and given/known data
    A 24.0 kg sample of ice is at 0.00°C. How much heat is needed to melt it? (For water Lf = 334 kJ/kg and Lv = 2257 kJ/kg.)

    A)5.42*10^4 kJ B)0.00 kJ C)8.02*10^3 kJ D)2.19*10^6 kJ

    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Jun 9, 2009 #2
    bigboss, as part of PF forum rules, you need to show some sort of attempt in order for us to help you. (Or else Borek will make you wear that wig!! :smile: )

    I am sure you know something about this problem...relevant equations.

    So, that being said, what do you think about this problem? What kind of concepts have you been talking/reading about in class?

    :smile:

    P.S. I got you started in your other thread.
     
  4. Jun 9, 2009 #3
    i beleive i have figured this out, q= M*Lf

    so 24*334= 8.02*10^3
     
  5. Jun 9, 2009 #4
    I am not sure about this. Do you know what you are doing here? Or are you just multiplying numbers until you get one of the offered answers? :smile:

    Like Borek asked: what do Lf and Lv stand for? (I know; I just want you to tell me)

    EDIT: Been awhile since I have dealt with heat; I think you are correct.
     
    Last edited: Jun 9, 2009
  6. Jun 9, 2009 #5

    Borek

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    Staff: Mentor

    Note: I asked, but then I deleted my post to not interfere.

    And honestly, I don't know. I can guess, but I have never seen these symbols used. Call it cultural difference :wink:
     
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