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Wave function problem

  1. Mar 1, 2010 #1
    1. The problem statement, all variables and given/known data
    The function

    [itex] \Psi(r) = A(2-{Zr\over a})e^-{Zr\over 2a} [/itex]

    gives the form of the quantum mechanical wavefunction representing the electron
    in a hydrogen-like atom of atomic number Z when the electron is in its first
    allowed spherically symmetric excited state. Here r is the usual spherical polar
    coordinate, but, because of the spherical symmetry, the coordinates θ and φ do
    not appear explicitly in Ψ. Determine the value that A (assumed real) must have
    if the wavefunction is to be correctly normalised, i.e. the volume integral of |Ψ|^2
    over all space is equal to unity.

    3. The attempt at a solution

    [itex] {\int \int \int}_R |\Psi|^2 dV = 1[/itex]

    [itex] \int _0^{\infty }\int _0^{2\pi }\int _0^{\pi }A^2e^{-\frac{Zr}{a}} \left(2-\frac{Zr}{a}\right)^2d\phi d\theta dr = 1[/itex]

    Which implies

    [itex] \int _0^{\infty }A^2e^{-\frac{\text{Zr}}{a}} \left(2-\frac{\text{Zr}}{a}\right)^2dr = {1\over 2\pi^2}[/itex]

    This turns out to be

    [itex] \frac{2aA^2}{Z} = \frac{1}{2\pi^2} [/itex]

    [itex] A = \pm \frac{\sqrt{\frac{z}{a}}}{2\pi} [/itex]

    This is wrong though?
    Is the problem the fact that Psi(r) isnt a function of theta or phi?
  2. jcsd
  3. Mar 1, 2010 #2


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