Wave Propagation Homework: Confirm Wave Equation & Obtain Velocity

AI Thread Summary
The discussion focuses on identifying which wave function represents a wave propagating at constant speed without changing its profile. The consensus is that the second function, y2, is the correct answer, as it maintains a constant amplitude while the others decrease over time due to the exponential decay factor. The participants confirm that y1 does not oscillate and behaves as a stationary wave, while y3 is a traveling wave that also experiences amplitude decay. There is a debate about the implications of imaginary wave speed, with clarification that it arises from a potential calculation error. The conversation concludes with an exploration of how different exponential functions behave over time, emphasizing the characteristics of each wave function.
EmmaK
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Homework Statement


Consider
y_1=Asin(5x)exp(-2t)
y_2=Aexp(4ix)exp(-2it)
y_3=Asin(2x-5t)exp(-2t)

(i)which one represents a wave that propagates at constant speed with no change in its profile
(ii)Confirm it satifies the wave equation and obtain the wave velocity
(iii)Comment qualitatively on the behaviour descried by the other 2


Homework Equations





The Attempt at a Solution


(i) i think it's the second one. I took the Re(y) and got Acos(3x-2t) so the amplitude is constant, while the other 2 will decrease in amplitude as exp(-2t) will tend to 0?

(ii)just differeniate it and stick into equation

(iii)They will oscillate with the same frequency but the amplitude will decrease?
 
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for (ii) i have just differentiated and subbed it into the wave equation and got v= 0.5i. can you have and imaginary wave speed?
 
EmmaK said:
for (ii) i have just differentiated and subbed it into the wave equation and got v= 0.5i. can you have and imaginary wave speed?
No, you must have dropped a factor of i somewhere.

Edit: Actually, you probably flipped a sign somewhere since the wave equation tells you what v^2 is.
 
Last edited:
EmmaK said:
Consider
y_1=Asin(5x)exp(-2t)
y_2=Aexp(4ix)exp(-2it)
y_3=Asin(2x-5t)exp(-2t)

(iii)They will oscillate with the same frequency but the amplitude will decrease?
Do you know what the effect is of the -5t in y3, in comparison to y1?
 
vela said:
Do you know what the effect is of the -5t in y3, in comparison to y1?
not really. isn't 5 the frequency? actually no.. because that would mean y1 has a frequency of 0...
 
EmmaK said:
not really. isn't 5 the frequency? actually no.. because that would mean y1 has a frequency of 0...
Actually, you're right. It's the frequency, so the first one doesn't oscillate at all. I'm not sure I'd call it a wave. The exponential factor in y1 and y3, as you mentioned above, just causes the amplitude to decrease over time.
 
ahhh ok thanks, so which doesn't change its profile. i thought 2 as it would keep repeating, but the actual height would be constantly changing
 
Oh, I hope you don't mean you're changing your answer to (i). You're right that the answer to (i) is y2.

The reason I asked about -5t was because in your answer to (iii) you said y1 and y3 both oscillated with the same frequency. Y3 oscillates, but y1 doesn't.
 
is the Re(y2) not A cos(4x-2t) instead of A cos(3x-2t) (posted above) cus how would you get to that answer?
 
  • #10
Yes, you're right. I think it was just a typo on Emma's part.
 
  • #11
but I am not understanding how this tells u that the wave propagates at constant speed with no change in its profile compared to the other two wave disturbances?
 
  • #12
and how can u tell that y1 is a stationary wave whose amplitude is decreasing exponentially with time and that y3 is a traveling wave also decreasing exponentially with time?
 
  • #13
What's the difference in how eiωt, e-iωt, e-ωt, and eωt behave? (Assume ω>0.) In particular, what do these functions do as t goes to ±∞?
 
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