Wave speed of the collision process in a line of cars

AI Thread Summary
The discussion revolves around deriving an equation for wave speed in a line of cars at a stoplight, focusing on the collision process. Participants emphasize the need to consider the nature of collisions, suggesting either perfectly inelastic or elastic collisions, with elastic being simpler to analyze. The concept of wave speed approaching infinity as distance approaches zero and the initial speed of the first car being transferred during collisions is highlighted. There is confusion regarding the time factor in the equations, with a suggestion that the disturbance's passage time should depend on the length of the cars. The conversation concludes with the notion that cars are treated as incompressible during collisions, affecting the dynamics of the wave speed.
snickersnee
Messages
30
Reaction score
0

Homework Statement



I need to write an equation for the at rest at a stoplight. Each car bumps into the one in front of it until the first car in line gets bumped.

Homework Equations


I found these equations for wave speed:
V=√(T/(m/L)), where T is tension, m is mass, L is length
and of course V=λf

The Attempt at a Solution


l8atx.jpg


But both those equations have a time factor, and I wasn't given any time information. All I know is that wave speed needs to approach infinity as x → 0, and wave speed approaches vo as x→∞
Any hints would be appreciated.
 
Physics news on Phys.org
snickersnee said:
I found these equations for wave speed:
V=√(T/(m/L)), where T is tension, m is mass, L is length
You don't have a string here.

I think you are supposed to assume that all collisions are either perfectly inelastic or elastic. The latter is easier to study: what is the speed of the first bumped car after the collision? How long does it take to make the next collision?
 
Yes we're assuming elastic collisions. The first bumped car is traveling at v0 because the car behind it transferred all its energy. The time until the next collision is
upload_2015-9-7_19-16-47.png
. I was thinking the total distance would be (4L+3x) and total time would be 3v0/(L+x) but then (total distance)/(total time) gives (4L^2+7xL+3x^2)/3v0 but that doesn't satisfy the limits required.
 
Why should the time change for longer cars (larger L) if the distance between the cars does not change?

Also, your fraction does not have units of time, it has units of inverse time.
 
mfb said:
Why should the time change for longer cars (larger L) if the distance between the cars does not change?

Also, your fraction does not have units of time, it has units of inverse time.

Thanks for your help. I think the time should change for longer cars because the disturbance takes longer to pass through that car, assuming the velocity of the disturbance is constant. And you're right, I should flip the fraction so it becomes
upload_2015-9-8_19-0-9.png
 
If the shock would travel at a speed of v (the same speed as the final car speed), your cars would get completely compressed to a single "disk" in the process - certainly not realistic.
Assume that the cars are incompressible (they cannot get deformed permanently in elastic collisions anyway) - as soon as the back of a car moves, the front moves as well.
 
Back
Top