Wavelength of a photon homework

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SUMMARY

The wavelength of a photon emitted when a hydrogen electron transitions from the n = 6 to the n = 3 energy level can be calculated using the energy levels defined by the Bohr model. The energy levels are given by E_n = E_1/n², where E_1 is -13.6 eV. By applying Planck's constant (6.626 x 10^-34 J s) and the energy difference between the two levels, the wavelength can be determined using the formula λ = hc/ΔE. This calculation confirms the principles outlined in Griffiths' "Introduction to Quantum Mechanics".

PREREQUISITES
  • Understanding of the Bohr model for hydrogen
  • Familiarity with quantum mechanics principles
  • Knowledge of energy level calculations in atomic physics
  • Proficiency in using Planck's constant and energy equations
NEXT STEPS
  • Calculate the wavelength of a photon using the formula λ = hc/ΔE
  • Explore the implications of energy level transitions in hydrogen
  • Study Griffiths' "Introduction to Quantum Mechanics" for deeper insights
  • Investigate the applications of the Bohr model in modern physics
USEFUL FOR

Students of quantum mechanics, physics educators, and anyone interested in atomic structure and photon emission processes.

Fiza43
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what is the wavelength of a photon emitted when a hydrogen electron drops from the n = 6 to the n = 3 level?
(E1 = -13.6 eV and Planck's constant is 6.626 * 10^-34 J s)
 
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Look up the Bohr model for hydrogen.
 
Or take a quantum mechanics book which will tell you that
[tex]E_n = - \frac{m}{2 \hbar^2} \left( \frac{e^2}{4 \pi \epsilon_0} \right)^2[/tex]
are the energy levels of a hydrogen atom (I checked this in Mathematica, filling in the numbers and n = 1 indeed gives -13.6057 ElectronVolt :D).

[edit] In fact, [tex]E_n = \frac{E_1}{n^2}[/tex] (Griffiths, Introduction to Quantum Mechanics, p. 149, [4.70]). Now if that doesn't make it easy on you, I give up :) [/edit]
 
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