If you have a second order PDE for a function \psi(x,t), it is of the general form
F(\partial_{tt}\psi,\partial_{xx}\psi,\partial_{xt}\psi,\partial_{t} \psi,\partial_{x}\psi,\psi)=g(x,t)
If the equation is linear, then F is linear with respect to all its arguments, i.e.
F(\partial_{tt}\psi,\partial_{xx}\psi,\partial_{xt}\psi,\partial_{t} \psi,\partial_{x}\psi,\psi,x,t)\\=a(x,t)\partial_{tt}\psi+b(x,t) \partial_{xx} \psi+c(x,t)\partial_{xt}\psi+d(x,t)\partial_{t} \psi+e(x,t)\partial_{x}\psi+f(x,t)\psi
There's no terms proportional to (\partial_{x}\psi)^{2} or something like that.
In the case of time-dependent SE for one 1D particle, we have d(x,t)=i\hbar, b(x,t)=\frac{\hbar^{2}}{2m}, f(x,t)=-V(x,t) and other coefficients are zero.