- #1
SigFig
- 8
- 0
Homework Statement
When calculating weights away from Earth's surface, for example:
At 6.38x10^3 km away from Earth's surface a spacecraft s weight is d=rE+rE or 2rE
Then F=(1/4)(SpaceCraftWeight)
What I don't understand is why the distance is rE+rE?
Or when 1.28x10^4 km away
d=rE+2rE or 3rE ?
I'm also assuming since F=mAmB/d^2
That's why F= (1/(x^2)(W) ?