Weight of a person on two planets with different masses

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A person weighing 250 N on one planet would weigh 500 N on a second planet with the same volume but twice the mass, due to the relationship between mass and gravitational force. The discussion highlights the importance of correctly applying the formula for gravitational force, g = Gme/re², and understanding that weight is directly proportional to gravitational acceleration. There was confusion regarding the calculation, with an incorrect figure of 1300 N initially mentioned, which was later clarified as a typographical error. Participants confirmed the correct reasoning and calculations, emphasizing the need for accuracy in problem-solving. Overall, the weight on the second planet is logically determined to be double that of the first.
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Homework Statement


A person standing on the surface of a planet has a weight of 250 N. Suppose he goes to another planet that is the same size(volume) but twice the mass(more dense). What would his weight be on the second planet?

Homework Equations



g=Gme/re2

The Attempt at a Solution


Hopefully, it is logical to assume that the planets are approximate spheres. In the problem, it is stated that the volume for the two problems is equivalent. Since the volume formula for a sphere is 4/3∏*3r, we can assume that the radii are equivalent. G is a constant. Logic would seem to dictate that the answer is twice the force on the first planet, so the answer would be 1300. However, the answer just doesn't feel right. I can't place it, but it seems like the answer is too simple. Could someone please confirm my answer, or if it's wrong, tell me the problem?

Thanks so much.
 
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You're right. Good job.
 
Thank you!
 
Though the volume of a sphere is \frac{4}{3}\pi r^3 not \frac{4}{3}\pi*3r!
 
Thank you! I remember now, when I looked it up I must have misread it.
 
Wait, how did you get 1300 from doubling 250 again?
 
I didn't. I somehow managed to type a 2 instead of a 6, even though the keys are nowhere near each other. Sorry for the confusion! Now it's a little concerning to me that others agreed when I typed the wrong number.
 
Medgirl314 said:
Now it's a little concerning to me that others agreed when I typed the wrong number.
No need. You've got it right.
 
Okay, thank you!
 
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