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SUMMARY

The discussion centers on calculating the moment required for a scoop to lift a sample of sand, clarifying the distinction between momentum and impulse. The formula p=mv represents momentum, where p is momentum, m is mass, and v is velocity. To achieve the desired acceleration of the mass, impulse, defined as force multiplied by the time it is applied, must be considered. A scoop can exert less force over a longer duration compared to a golf club, which applies force for a brief moment.

PREREQUISITES
  • Understanding of momentum (p=mv)
  • Knowledge of impulse (Force x Time)
  • Familiarity with basic physics concepts related to force and motion
  • Experience with practical applications of force in sampling techniques
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  • Research the principles of impulse and its applications in physics
  • Explore the mechanics of different sampling tools and their force applications
  • Study the relationship between force, time, and acceleration in practical scenarios
  • Investigate case studies on effective sampling techniques in various materials
USEFUL FOR

Physics students, engineers, and professionals involved in material sampling and analysis will benefit from this discussion, particularly those interested in the mechanics of force and motion.

ExoP
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Hi,

I was thinking of something: How are one supposed to calculate the moment needed for a scoop to scoop up a sample of e.g. sand? Does the classical p=mv work? Any ideas or comments?
 
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It's not clear what you mean by your question; it is clearly in a particular context.
P=mv is the momentum of a mass m with velocity v.
A certain Impulse will be needed to accelerate a mass m to velocity v and Impulse is Force times the time it is applied. A small force takes more time to do the job than a large force. I think you may be referring to Impulse rather than the "moment" (=Momentum) in your post.

If you are, in fact, scooping sand, then the scoop could provide less force over a longer time than for, as an example, a golf club, which may have contact for a small fraction of a second. These are general comments and a more useful answer could be given if there were more detail about the actual sampling job you have in mind.
 

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