Proving the Relation Between Weyl Tensor, Ricci Tensor & Scalar

sroeyz
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Hello, I wish to show that on 3-dimensional manifolds, the weyl tensor vanishes.
In other words, I want to show that the curvature tensor, the ricci tensor and curvature scalar hold the relation

eq0009MP.gif


Please, if anyone knows how I can prove this relation or refer to a place which proves the relation, I will be most grateful.

Thanks in advance
 
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You have created an identical thread in the Physics area. Please don't double post.
 
Hey! Jim McNamara ...

Excuses Excuses Jim McNamara.

I was interested in his question. I find it obnoxious that someone that didn't even participate in providing him with an answer in the physics section has the audacity to chid him for being interested in asking a larger audience.

In another person's post about unitary matrices you tried answering with some nonsense, that Matt grime cleaned up.

In a post called complex.h . You again gave bogus statements that were cleaned up by Hurkyl.

In a post Atomic number and Orbitals. You again make a God like statement about passing on answering it as you think it is someone's homework and it is incomprehensible. But others gave him a clear answer.

In Asymptotic mathcing for a first order differential equation post . You again declare that a variable "e" in some equation must refer to Napier's constant. At least there you start with "I'M CONFUSED".

In Sulfur Based Lifeforms Question post . You don't even get that the point is that we are carbon based life forms.

I am not in charge of this forum. But please don't TELL anyone else anything, ok. (Especially about math, it isn't based on an opinion which you obviously want to flaunt).

Steve
 
the long and short of the proof is: first show that the tensor is skew-symmetric in any two variables; then take a basis of TM and plug them into the weyl tensor; the weyl tensor is a 4-tensor, so one of the basis elements has to double up; hence it's zero.
 
Hello! There is a simple line in the textbook. If ##S## is a manifold, an injectively immersed submanifold ##M## of ##S## is embedded if and only if ##M## is locally closed in ##S##. Recall the definition. M is locally closed if for each point ##x\in M## there open ##U\subset S## such that ##M\cap U## is closed in ##U##. Embedding to injective immesion is simple. The opposite direction is hard. Suppose I have ##N## as source manifold and ##f:N\rightarrow S## is the injective...
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