What am I doing wrong with the AMU conversion?

  • Thread starter Thread starter Sunny1261
  • Start date Start date
AI Thread Summary
The discussion revolves around calculating the mass defect of cobalt-59 and converting it from kilograms to atomic mass units (AMU). The user successfully calculated the mass defect in kilograms as 8.999737e-28 Kg. They are struggling with the conversion to AMU, having obtained a value of 0.5419895815 AMU, which is not being accepted by Webassign. The correct conversion method involves dividing the mass in kilograms by the conversion factor of 1.6605e-27 Kg per AMU. Clarification on the calculation process and ensuring the correct input format for Webassign is needed for successful submission.
Sunny1261
Messages
11
Reaction score
0

Homework Statement


Determine the mass defect of the nucleus for cobalt 5927Co, which has an atomic mass of 58.933 198 u. Express your answer in AMU and Kg.

Homework Equations


How do I get the AMU? Or Atomic Mass Unit?

The Attempt at a Solution


Ok, so I solved the answer in Kg. The answer in Kg is 8.999737e-28 Kg (This answer is correct). And I need to provide the answer in Atomic Mass Units also. I know the conversion factor is 1 amu = 1.6605e-27 Kg. My answer is .5419895815, but Webassign is not accepting the answer. Please help.
 
Physics news on Phys.org
I don't have a calculator near to me at the moment but all you need to do is divide your answer by 1.6605e-27 to get the units in amu
 
The number i plugged into webassign is the Kg divided by the conversion factor...
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top