What Angle Makes a Projectile Travel Equally in X and Y Directions?

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SUMMARY

The angle (theta) that allows a projectile to travel the same distance vertically as horizontally is 45 degrees. This conclusion is derived from the equations of motion for projectile motion, specifically using the equations ViSin(theta)(time) - 1/2at^2 = delta Y and ViCos(theta)(2time) = delta X. By equating the vertical and horizontal distances, it is established that the range equals the maximum altitude when theta is set to 45 degrees. The relevant resources for further understanding include HyperPhysics links on projectile motion.

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Homework Statement


I need to find the angle (theta) that when an object is launched from it, it will go the same distance vertically as horizontally. So if it went 100 feet up in the Y axis it also went 100 feet in the X axis. Thanks.
ps. can you show me how you got this answer?


Homework Equations


ViSin(theta)(time) - 1/2at^2 = delta Y

ViCos(theta) (2time) = delta X

The Attempt at a Solution


ViSin(theta)(time) - 1/2at^2 = ViCos(theta) (2time)
 
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