What are the components of force in 3D for a pulled atom?

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SUMMARY

The discussion centers on the components of force in three-dimensional space when pulling an atom within a body-centered cubic (BCC) lattice. When a force F is applied in any direction (x, y, or z), the force component in that direction equals F, while the components in the other two directions remain zero. The symmetry of the BCC lattice ensures that forces exerted in one direction do not induce movement in the perpendicular directions, confirming that only the direction of the applied force experiences displacement.

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Gogsey
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This not so much of a homework proble, but something I need to visualize and understand to do a homework problem.

If theeres and atom at x,y,z = 0, and one located at x,y,z, = 1/2 and we pull second atom from its posistion with a force F in anyone of the x,y,z directions, what are the components of the force in the x,y and z directions?

I thought that if you pulled it in any of the directiosn, each coponent would be equal and add to give F. So, 1/3 of the force would be in each of the x,y,z directions no matter if you add a force F in x,y, or z.

I have trouble picturing what's happening in 3D.
 
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Gogsey said:
and we pull second atom from its posistion with a force F in anyone of the x,y,z directions, what are the components of the force in the x,y and z directions?

Well, the component of force will be F in direction you choose to pull it and 0 in rest directions.

Gogsey said:
I thought that if you pulled it in any of the directiosn, each coponent would be equal and add to give F. So, 1/3 of the force would be in each of the x,y,z directions no matter if you add a force F in x,y, or z.
I really can't understand what you are trying to say
 
The picture is a bcc lattice with all the atoms connected to each other.m Now ere onlt consideruing the effects of moving each atom on the centrakl atom. So applying a force in each dimension, and seeing what happens to the atiom in the centre of the cube.

So put a force in the x direction, and see what the restoring force is in x, y and z directions. And we do thies for all 9 atoms including moving the one at the centre of the cude and seeing theeffect on all others.

I guess because of symmetry, there will be zero movement in the y direction, when applyong aforce in the x direction, same for yz and xz combinations. So there should only be a movement in the x direction when there a force along x, and same for yy, and zz.

If we say the atom at the centre is at (0,0,0) and the other ones are are +/-x,+/-y,+/-z, so eight atoms. I was wondering if there woul;d be changes in position to the other atoms in all directions, no matter the direction of the force. But because of symmetry, al lot of these forces will cancel out.
 

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