What Are the Energy and Angles of Photons from \(\pi_{0}\) Meson Decay?

AI Thread Summary
The discussion focuses on the decay of the \(\pi_{0}\) meson into two photons, addressing the energy and angles of the resulting photons. In the rest frame of the meson, each photon has an energy of \(\frac{m_{\pi}}{2}c^{2}\) due to conservation of momentum, as they travel in opposite directions. The angle of one photon is given as \(\theta\), leading to the claim that the other photon’s angle is \(\pi - \theta\). However, there is a suggestion that this angle may be incorrect, prompting a request for clarification and a more formal derivation of the solutions. The discussion highlights the need for a deeper understanding of the conservation laws in particle physics.
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Homework Statement



(i) The \pi_{0} meson predominantly decays into two photons.

(a) Write down an expression for the energy of each photon in the \pi_{0} rest frame in terms of the \pi_{0} mass m_{\pi}. [2 marks]

(b) One of the photons is produced at spherical polar angle \theta with respect to the positive z axis in the \pi_{0} rest frame. What is the corresponding spherical polar angle of the other photon? [2 marks]


Homework Equations



Energy of a particle in its rest frame = mc2.


The Attempt at a Solution



In the rest frame of the meson, the meson is at rest. So, its momentum is zero. By the law of conservation of momentum, therefore, the two photons have a total momentum equal to zero. So, the photons must be traveling in opposite directions with the same magnitude of momentum.

(a) The photons have the same magnitude of momentum. So, each must have half the rest energy of the meson. So, energy of each photon = \frac{m_{\pi}}{2}c^{2}.

(b) The photons must be traveling in opposite directions. So, the corresponding spherical polar angle of the other photon is \pi - \theta.

I would greatly appreciate if you could point out any mistakes and make some comments on my solutions.
 
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This should probably have been posted in the advanced physics section I think.. It's certainly not introductory.It seems that your angle is wrong. \pi-\theta[\itex] would give you the negative of the angle you are looking for.<br /> <br /> But part (a) seems right. I would only recommend that you try to show it in a more formal mathematical way.<br /> Write out the expressions for conservation of momentum and conservation of energy and then derive the answer from that.
 
If \pi-\theta[\itex] is not the answer, I can&#039;t think of any other answers. What could it possiby be?<br /> <br /> Alos, I am not sure how I could write the solutions in a more formal way. I would be grateful if you could take a bit of your time to show the steps.
 
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