What are the equations for finding common tangents between two curves?

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To find the equations of common tangents between the curves y²=4ax and x²=4by, one must first derive the equations of tangents for each curve. The derivatives of both curves are equated, leading to the relation 2a/y = x/2b. The next step involves substituting this relation into the point-slope form of the line equation. The discussion highlights a common challenge of dealing with complex cube roots during the calculations. A suggested approach is to first derive the general tangent equations for each curve separately before finding their common tangents.
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Homework Statement



Finding the equations of common tangents of y^{2}=4ax and x^{2}=4by

Homework Equations



Equating both curves' derivatives :
\frac{2a}{y}=\frac{x}{2b}

The Attempt at a Solution



Calculated both of the curves' derivatives and equated them .
Used the resulting relation in two point form of straight line equation (y-y1)=m(x-x1) .

Got Stuck now! with too many cuberoots .
 
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In your equation: \displaystyle \frac{2a}{y}=\frac{x}{2b}\,, the y is from a point on the first curve, the x from a point on the second curve.

Instead, start by doing the following:

Find the general equation for a line tangent to y2=42x.

The find the general equation for a line tangent to x2=4by.
 
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