What Are the Equations for Nuclear Magnetic Resonance in Water?

steph_mil
Messages
5
Reaction score
0

Homework Statement



Nuclear magnetic resonance in water is due to the protons of hydrogen. Find the field necessary to produce NMR (nuclear magnetic resonance) at 60 MHz.

Homework Equations



These are the equations I think I'm supposed to use:

omega (subscript zero) = gamma * B (subscript zero) (omega is frequency, B is magnetic field)

B sub 0 = (omega sub zero) / (ge/2m)

The Attempt at a Solution



I know that gamma = ge/2m, and g is the gyromagnetic ratio, but do I use g for electrons (g = 2?) and e as the electron charge? The problem states that the nuclear magnetic resonance in water is due to protons, so do I use the g for water? e can only be one thing, right (1.6 * 10^-19) and for m, do I use the mass of an electron or a proton? The equations are not complicated for this problem, but I'm confused about what constants to use (protons or electrons?). Please help!

Thanks!
 
Physics news on Phys.org
ok, so I should use the g-factor for a proton that you gave. And I should use e = 1.6*10^-19, and I should use m = 9.11 X 10^-31 kg? Using that the magnetic field is equal to the frequency divided by ge/2m, I should be able to solve for the field that would produce nuclear magnetic resonance at MHz?
 
no should use the mass of the proton.

Use Si units all the way, then you should get the answer in Hz
 
steph_mil said:
ok, so I should use the g-factor for a proton that you gave. And I should use e = 1.6*10^-19, and I should use m = 9.11 X 10^-31 kg? Using that the magnetic field is equal to the frequency divided by ge/2m, I should be able to solve for the field that would produce nuclear magnetic resonance at MHz?


you got the correct value?
 
##|\Psi|^2=\frac{1}{\sqrt{\pi b^2}}\exp(\frac{-(x-x_0)^2}{b^2}).## ##\braket{x}=\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dx\,x\exp(-\frac{(x-x_0)^2}{b^2}).## ##y=x-x_0 \quad x=y+x_0 \quad dy=dx.## The boundaries remain infinite, I believe. ##\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dy(y+x_0)\exp(\frac{-y^2}{b^2}).## ##\frac{2}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,y\exp(\frac{-y^2}{b^2})+\frac{2x_0}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,\exp(-\frac{y^2}{b^2}).## I then resolved the two...
Hello everyone, I’m considering a point charge q that oscillates harmonically about the origin along the z-axis, e.g. $$z_{q}(t)= A\sin(wt)$$ In a strongly simplified / quasi-instantaneous approximation I ignore retardation and take the electric field at the position ##r=(x,y,z)## simply to be the “Coulomb field at the charge’s instantaneous position”: $$E(r,t)=\frac{q}{4\pi\varepsilon_{0}}\frac{r-r_{q}(t)}{||r-r_{q}(t)||^{3}}$$ with $$r_{q}(t)=(0,0,z_{q}(t))$$ (I’m aware this isn’t...
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
Back
Top