What are the horizontal asymptotes of cot^-1(x)?

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The discussion clarifies that cot^(-1)(x) is another notation for arccot(x), which is the inverse function of cotangent. It emphasizes that the "-1" in this context signifies an inverse function, not a reciprocal. The confusion arises from the relationship between cotangent and its inverse, as well as the nature of asymptotes. Cotangent has vertical asymptotes, but arccotangent does not have horizontal asymptotes in the same way. Understanding these distinctions is crucial for grasping the behavior of these functions.
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What are the horizontal asymptotes of
cot^(-1)x
I don't understand because isn't that tangent and it has asymptotes?!
 
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So.. why is arccotangent cot(1/x)... I don't understand.
 
It isn't. It also is not 1/cot(x) which is tan(x).

When working with functions, the "exponent" -1 does not mean "reciprocal" (and isn't really an exponent). It means "inverse function".

cot-1(x) is just another notation for arccot(x), the inverse function to cot(x).
Specifically, if y= cot-1(x)= arccot(x), then x= cot(y). Notice that you have swapped x and y so the graphs will swap x and y axes. Where does cotangent have vertical asymptotes?
 
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