What Are the Implications of a New Relativistic Quantum Theory?

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The discussion revolves around a new relativistic quantum theory proposed in Eugene Stefanovich's book "Relativistic Quantum Dynamics," which aims to provide a consistent framework for interacting particles without the need for renormalization. The theory challenges traditional views by suggesting that classical electrodynamics can be formulated without electric and magnetic fields, using direct potentials instead. Critics question the derivation of Maxwell's equations from this new approach, emphasizing the importance of maintaining established engineering practices based on classical electromagnetism. Stefanovich argues that while Maxwell's equations are useful for macroscopic cases, they fall short in describing systems with few charges, where his particle-based theory offers clearer insights. The conversation highlights the tension between established theories and innovative approaches in theoretical physics.
  • #121
meopemuk said:
The kindergarten formula guarantees that the probability is always between 0 and 1, which is kind of nice. Does the expert formula offer the same guarantee? I don't see it, even in the case when the detector efficiency alpha=1.
The expert formula is derived under the assumption that alpha T is small, since higher order terms are neglected in the derivation. Thus p<<1.

The kindergarden formula is underspecified since you are not saying which volume is the relevant volume. So it says nothing about the actual experimental situation.
meopemuk said:
In general, I think we are separated by a big philosophical divide. I prefer to think that if there was a sparkle on a luminescent screen, this simply means that an electron (which is a tiny particle) hit exactly at this location.
Yes, we are at opposite sides of the particle -wave spectrum of interpretations.
meopemuk said:
You represent the electron as a continuous extended field, which somehow excites atoms in the entire screen. This excitation conspires to produce a sparkle at a single location.
Nothing needs to conspire; each excitable atom acts independently of the other, according to the incident intensity.
meopemuk said:
The location of the sparkle is sort of unpredictable, because of the chaotic behavior of the atoms in the screen.
Yes. This is what the usual semiclassical analysis reveals. Under ordinary circumstances, quantum corrections are tiny and can be neglected.
meopemuk said:
These are two completely different views on quantum mechanics and on the origin of quantum uncertainties. They are as different as the corpuscular and wave pictures of the world.
Yes, and the modern view is that Nature is governed by quantum field theory, not by Schroedinger equations for many-particle systems.
meopemuk said:
If you know an experiment where this picture fails completely, this would be a big shock to me.
We are going in circles. I had mentioned spontaneously broken theories, etc.. But you discounted as pure speculation what others found worthy of a Nobel prize.
 
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  • #122
A. Neumaier said:
The expert formula is derived under the assumption that alpha T is small, since higher order terms are neglected in the derivation. Thus p<<1.

But when I shine one photon on the photographic plate I get the detection probability of almost 1. Is your theory applicable in this case?

A. Neumaier said:
The kindergarden formula is underspecified since you are not saying which volume is the relevant volume. So it says nothing about the actual experimental situation.

V^3 is the volume of the particle detector. This could be the volume of the photographic plate, for example.


A. Neumaier said:
We are going in circles. I had mentioned spontaneously broken theories, etc.. But you discounted as pure speculation what others found worthy of a Nobel prize.

Well, I've asked you about *experimental* refutation of the probability interpretation of wave functions. You are talking about *theories*, which are not confirmed yet, by the way.

Eugene.
 
  • #123
A. Neumaier said:
For example, Landau & Lifgarbagez begin in Section 2 of their Vol. 3 with such a statement, but immediately replace it in (2.1) and (3.10) by the more correct version about the interpretation of the expectation value <K> = Psi^* K Psi, where K is an arbitrary observable (linear integral operator) depending on the form and values of the measurement. From then on, only the latter interpretation is used; never the fictitious, idealized introductory remark.

The probability

\int_{V} |\psi(x)|^2 dx


can be also regarded as expectation value. In this case the Hermitian operator of observable is the projection on the subset V of the position operator spectrum. This observable can be characterized as a "yes-no experiment" or a question "is the particle present in the volume V?"

Eugene.
 
  • #124
A. Neumaier said:
It [the probabilistic interpretation of wave function] is stated in the beginning as an interpretation aid without proof, and never taken up again in the context of real measurements where the claim would have to be justified. It is very common to make this sort of idealized assumption to get started; but once the formalism is established, this assumption is never used again.


The probabilistic interpretation is the centerpiece of the quantum logic approach to quantum mechanics. See chapter 1 in my book. In this approach, quantum mechanics is nothing but a modified (rather generalized) version of the probability theory. The probabilistic interpretation is used everywhere where QM is applied. The most basic things calculated in QM are probabilities of measurements. How are you going to get them without wave function and its probabilistic interpretation? I am very surprised to learn that other opinions exist on this matter.

Eugene.
 
  • #125
A. Neumaier said:
Nothing needs to conspire; each excitable atom acts independently of the other, according to the incident intensity.

No, there is a huge conspiracy there. In your theory, before approaching the screen the electron is represented by a continuous field. This means that the electron charge is spread over large area. Nevertheless, the "click" occurs only in one place. I hope you wouldn't deny the fact that after the "click" the full electron charge resides in the neighborhood of the "clicked" atom. So, somehow this charge density cloud has condensed at one point. Not at two points, not at three points - always at one point. What is the explanation of this mysterious behavior?

The idea of independent excitable atoms does not seem to be a good explanation. It seems that all atoms in the screen agree to choose one of them as the "condensation" point and to send their portion of the incident electron's charge density exactly to this point. I call it a conspiracy.

Eugene.
 
  • #126
meopemuk said:
The idea of independent excitable atoms does not seem to be a good explanation. It seems that all atoms in the screen agree to choose one of them as the "condensation" point and to send their portion of the incident electron's charge density exactly to this point. I call it a conspiracy.
If that is a conspiracy, then all the experiments done with Alice and Bob point to the same sort of conspiracy between far away particles in your favored interpretation.
This only proves that this sort of conspiracy is an unavoidable feature of QM.
 
  • #127
A. Neumaier said:
If that is a conspiracy, then all the experiments done with Alice and Bob point to the same sort of conspiracy between far away particles in your favored interpretation.
This only proves that this sort of conspiracy is an unavoidable feature of QM.

Are you talking about entanglement?

I think that the conspiracy you are suggesting is much more troubling than entanglement. Your approach needs a real flow of charge density to one point from around the entire area of the detector. This is despite the fact that significant electrostatic repulsion needs to be overcome in order to concentrate the charge in one place. It seems that this flow of charge density can happen equally effectively independent on whether the detector is a conductor or an insulator.

On the other hand, nothing of that sort is needed in the particle interpretation. The "click" happens simply because a point-like electron hits the atom. End of story.

Eugene.
 
  • #128
meopemuk said:
[...]
So, somehow this charge density cloud has condensed at one point.
Not at two points, not at three points - always at one point.

It's misleading to say "always at one point". One must take account of the
time interval in the formula. There's a nonzero probability for more than
one click in a given time interval (assuming the incident beam remains "on").
And if one makes the time interval very small there's a very good
chance that nothing at all happens at any given point on the detector.

Such information involving time intervals is missing if one relies
only on the over-simplified picture that |\psi(x)|^2 is the
probability for finding the particle at x.
 
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  • #129
This is an argument you don't get to witness first hand too often. Take notes kids.
 
  • #130
strangerep said:
It's not "always at one point". One must take account of the time interval
in the formula. There's a nonzero probability for more than one click in
a given time interval (assuming the incident beam remains "on").
And if one makes the time interval very small there's a very good
chance that nothing at all happens at any given point on the detector.

Such information involving time intervals is missing if one relies
only on the over-simplified picture that |\psi(x)|^2 is the
probability for finding the particle at x.

But I have arranged my experiment so that only one electron was emitted. So, if the detector's efficiency is 1, I must get one and only one click, provided that I've waited long enough to allow the electron to reach the detector.

Eugene.
 
  • #131
meopemuk said:
But I have arranged my experiment so that
only one electron was emitted.

Where did you "arrange" that? I scanned back through the earlier posts,
but didn't see the experimental arrangement described.

So, if the detector's efficiency is 1, I must get one and only one click,
provided that I've waited long enough to allow the electron to reach the detector.

Then you don't have an ensemble, so an interpretation involving probability
becomes problematic. If you do set up many repetitions of the experiment,
it's indistinguishable from a very low intensity beam striking a target.
 
  • #132
strangerep said:
Where did you "arrange" that? I scanned back through the earlier posts,
but didn't see the experimental arrangement described.

Sorry if it wasn't clear. In our discussions with Arnold we went back and forth between different threads, so this piece of info could be lost. In my posts I've always assumed emission of particles one-by-one. Here I've intentionally switched from photons (whose one-by-one emission can be problematic) to electrons, which can be easily emitted one-by-one, carry a unit charge and cannot be divided into smaller pieces.


strangerep said:
Then you don't have an ensemble, so an interpretation involving probability
becomes problematic. If you do set up many repetitions of the experiment,
it's indistinguishable from a very low intensity beam striking a target.

I shoot one electron and get one dot on the luminescent screen or whatever detector was chosen. This is one member of the ensemble. Then I shoot the second electron and get the second dot in a different place. This is the second member of the ensemble. Then I repeat this procedure as many times as needed in order to form a representative ensemble of measurements. I am sure that each electron has produced a single dot for me. I also see that the distribution of dots on the screen forms a characteristic interference pattern. (I am doing the double-slit experiment here.)

From these observations I make a few conclusions:

1. Electrons are point-like particles, and luminescent sparkles are created by direct hits of incident electrons.

2. For each area of the detector I can measure the probability of it being hit by electrons. This is the number of electrons that have landed in this area divided by the total number of electron emitted.

3. For this double-slit setup I can calculate 1-electron quantum-mechanical wavefunction in the vicinity of the screen. Taking square of this wavefunction and integrating over area I get exactly the same probability as the one measured in 2.

So, standard 1-electron quantum mechanics gives a perfect description of the double-slit experiment in the corpuscular picture.

Eugene.
 
  • #133
meopemuk said:
I think that the conspiracy you are suggesting is much more troubling than entanglement. Your approach needs a real flow of charge density to one point from around the entire area of the detector.
Unobservable fictions of the imagination need not be conserved.

The observable charge flow is the expectation of the current operator defined by the electron field. It satisfies the continuity equation rigorously and hence fully accounts for charge conservation.
 
  • #134
A. Neumaier said:
The observable charge flow is the expectation of the current operator defined by the electron field. It satisfies the continuity equation rigorously and hence fully accounts for charge conservation.


I don't dispute the fact that the total charge is conserved in your model. But I don't understand what is the mechanism that forces this charge density to condense to one point against the force of Coulomb repulsion.

Eugene.
 
  • #135
meopemuk said:
I don't dispute the fact that the total charge is conserved in your model. But I don't understand what is the mechanism that forces this charge density to condense to one point against the force of Coulomb repulsion.
The continuity equation not only tells that the total charge is conserved but also that at _every_ point in space and _every_ moment in time the inflow and outflow of charge balance exactly in the ensemble mean.

Nowhere in quantum mechanics one can have better conservation laws for energy and momentum - not even in the quantum mechanics of two nonrelativistic particles.

Thus requiring it of charge is unreasonable (and in fact untestable).
 
  • #136
A. Neumaier said:
The continuity equation not only tells that the total charge is conserved but also that at _every_ point in space and _every_ moment in time the inflow and outflow of charge balance exactly in the ensemble mean.

Nowhere in quantum mechanics one can have better conservation laws for energy and momentum - not even in the quantum mechanics of two nonrelativistic particles.

Thus requiring it of charge is unreasonable (and in fact untestable).

Sorry, I don't understand your point here. I was not questioning the validity of continuity equation in your model. I can even close my eyes on non-conservation of energy and momentum. But what is really strange is the ability of the charge density to shrink to a point in some instances. This is reminescent of the QM wave function collapse, but much more troubling, because in your case the collapsing thing is not the imaginary probability density amplitude (as in QM), but real physical charge density.

Eugene.
 
  • #137
meopemuk said:
Sorry, I don't understand your point here. I was not questioning the validity of continuity equation in your model.
You raised the objection that charge must flow to the firing point, and I replied that the continuity equation proves that nothing can be wrong with the flow of charge. (Tiny flows of charge happen all the time in a macroscopic body.)
meopemuk said:
I can even close my eyes on non-conservation of energy and momentum.
You have to close your eye on non-conservation of momentum already if you consider a particle picture of a double slit experiment!
meopemuk said:
But what is really strange is the ability of the charge density to shrink to a point in some instances. This is reminiscent of the QM wave function collapse, but much more troubling, because in your case the collapsing thing is not the imaginary probability density amplitude (as in QM), but real physical charge density.
The charge flows to the point where it is needed. It doesn't need to contract miraculously and instantly from everywhere. The fired electron removes charge locally, and this local deficiency is corrected for by inflow of a little bit of charge density from the neighborhood. (It is not really different from the flow of water in a bucket that has a little hole at the bottom from which drops leak out at random times, while the compensating inflow happens steadily at some other place.) The covariance and locality of quantum field theory ensures that nothing happens instantly.
 
  • #138
A. Neumaier said:
The charge flows to the point where it is needed. It doesn't need to contract miraculously and instantly from everywhere. The fired electron removes charge locally, and this local deficiency is corrected for by inflow of a little bit of charge density from the neighborhood. (It is not really different from the flow of water in a bucket that has a little hole at the bottom from which drops leak out at random times, while the compensating inflow happens steadily at some other place.) The covariance and locality of quantum field theory ensures that nothing happens instantly.

I don't find your explanation convincing. I don't know of any physical force that would suck the whole widely distributed charge density to a single point. Charge densities normally have the tendency of self-repulsion. Here we have an example of a completely opposite effect. What kind of Maxwell equation can be written to demonstrate such an abnormal behavior?

Eugene.
 
  • #139
meopemuk said:
I don't find your explanation convincing. I don't know of any physical force that would suck the whole widely distributed charge density to a single point. Charge densities normally have the tendency of self-repulsion. Here we have an example of a completely opposite effect. What kind of Maxwell equation can be written to demonstrate such an abnormal behavior?
There is a nontrivial and very rugged charge distribution already in the detector before anything arrives at it. Even in a single molecule like water you have a nontrivial charge distribution - one of the reasons water behaves as it does. This charge distribution changes and adapts continuously while the arriving wave reaches the body, and it keeps doing so during the time it takes to emit the electron.

Thus everything happens continuously, in conformance with the continuity equation. Nothing needs to be sucked into a point - the emitted electron is itself a moving charge distribution, radially expanding in its rest frame.
 
  • #140
A. Neumaier said:
Nothing needs to be sucked into a point - the emitted electron is itself a moving charge distribution, radially expanding in its rest frame.

According to you, before the measurement the electron had the form of a charge density cloud extending over the range of several centimeters. After the measurement we see that one CCD pixel has its charge changed by -e, while all other pixels stay with the same (=0) charge. This looks like "sucked into a point" to me. How this behavior can be achieved by a "moving charge distribution, radially expanding in its rest frame"?

Eugene.
 
  • #141
meopemuk said:
According to you, before the measurement the electron had the form of a charge density cloud extending over the range of several centimeters. After the measurement we see that one CCD pixel has its charge changed by -e, while all other pixels stay with the same (=0) charge. This looks like "sucked into a point" to me. How this behavior can be achieved by a "moving charge distribution, radially expanding in its rest frame"?
The charges are only moved a little, not concentrated to a point from everywhere:
A charge-coupled device (CCD) is a device for the movement of electrical charge, usually from within the device to an area where the charge can be manipulated, for example conversion into a digital value. This is achieved by "shifting" the signals between stages within the device one at a time. CCDs move charge between capacitive bins in the device, with the shift allowing for the transfer of charge between bins.
Often the device is integrated with an image sensor, such as a photoelectric device to produce the charge that is being read
(taken from http://en.wikipedia.org/wiki/Charge-coupled_device )
 
  • #142
A. Neumaier said:
The charges are only moved a little, not concentrated to a point from everywhere:

Well, then we disagree on the meaning of the words "moved" and "concentrated".

Eugene.
 
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  • #143
Arnold,

I think we don't understand each other, because we are talking about different charges. The wikipedia article is talking about the charge, which moves from "an image sensor, such as a photoelectric device" to "an area where the charge can be manipulated, for example conversion into a digital value". All this charge movement occurs within one CCD array pixel in a well controlled fashion. This is a part of the registration process, i.e., the part of the process, which records the fact that the "image sensor" of that pixel has picked up some signal from an impinging photon or electron or some other external particle.

I was talking about the charge density wave, which you attribute to the single electron, which impinges on the CCD array from the outside. The integral of this charge density is equal to the electron's charge -e. When this wave approaches the array of CCD detectors, its density is distributed across a large area covering many pixels. However, only one pixel produces a signal. The whole initial charge (-e) of the wave gets concentrated within this one pixel. So, apparently, the initial distributed charge density has shrinked to the size of one pixel. This charge movement/migration/concentration/collapse happens across the whole area of the detector array. This abrupt shrinkage is different from the controlled charge migration in the circuitry attached to one particular pixel as described in the wikipedia article.

Eugene.
 
  • #144
meopemuk said:
I think we don't understand each other, because we are talking about different charges.
Yes. You ignore all the charge that is already present in the CCD, and concentrate on the charge of the electron - of course if you do that, everything looks strange. But once you take into account the complete charge field, including that of the CCD, everything falls into place.
meopemuk said:
The wikipedia article is talking about the charge, which moves from "an image sensor, such as a photoelectric device" to "an area where the charge can be manipulated, for example conversion into a digital value". All this charge movement occurs within one CCD array pixel in a well controlled fashion. This is a part of the registration process, i.e., the part of the process, which records the fact that the "image sensor" of that pixel has picked up some signal from an impinging photon or electron or some other external particle.

I was talking about the charge density wave, which you attribute to the single electron, which impinges on the CCD array from the outside. The integral of this charge density is equal to the electron's charge -e. When this wave approaches the array of CCD detectors, its density is distributed across a large area covering many pixels. However, only one pixel produces a signal. The whole initial charge (-e) of the wave gets concentrated within this one pixel. So, apparently, the initial distributed charge density has shrinked to the size of one pixel. This charge movement/migration/concentration/collapse happens across the whole area of the detector array. This abrupt shrinkage is different from the controlled charge migration in the circuitry attached to one particular pixel as described in the wikipedia article.
Nothing shrinks abruptly. The new charge of total amount -e arrives continuously , thereby changing the charge distribution of the CCD continuously. This changing charge distribution undergoes a continuous evolution according to the laws of QM.
When a random pixels produces a signal, the local charge near that pixel is rearranged. Nowhere is there any shrinking or any abrupt change in the charge distribution.
 
  • #145
A. Neumaier said:
Nothing shrinks abruptly. The new charge of total amount -e arrives continuously , thereby changing the charge distribution of the CCD continuously. This changing charge distribution undergoes a continuous evolution according to the laws of QM.
When a random pixels produces a signal, the local charge near that pixel is rearranged. Nowhere is there any shrinking or any abrupt change in the charge distribution.

Please let me know where is the gap in my logic: Suppose that we have a 1000X1000 CCD array with 1000000 pixels. Before the experiment the total charge of each pixel and attached circuitry is around zero. We send one electron in the form of a spread-out wave toward the array. The total charge of the electron wave is -e. The amount of charge projected onto each pixel is -e/1000000. So, just after the wave has touched the array the total charge of each pixel is -e/1000000. Then, according to you, some charge migration occurs between the pixels, so that the whole initial charge -e gets concentrated in one and only one pixel.

You say that this charge rearrangement occurs due to "a continuous evolution according to the laws of QM". I am wondering, what kind of physical interaction is responsible for such an unusual charge rearrangement? Are there any references discussing this interesting effect?

Eugene.
 
  • #146
meopemuk said:
Please let me know where is the gap in my logic: Suppose that we have a 1000X1000 CCD array with 1000000 pixels. Before the experiment the total charge of each pixel and attached circuitry is around zero.
In this approximation, the charge arriving from the electron wave is also around zero.
So your argument amounts to redistributing around zero charge.
meopemuk said:
We send one electron in the form of a spread-out wave toward the array. The total charge of the electron wave is -e. The amount of charge projected onto each pixel is -e/1000000. So, just after the wave has touched the array the total charge of each pixel is -e/1000000. Then, according to you, some charge migration occurs between the pixels, so that the whole initial charge -e gets concentrated in one and only one pixel.

You say that this charge rearrangement occurs due to "a continuous evolution according to the laws of QM". I am wondering, what kind of physical interaction is responsible for such an unusual charge rearrangement? Are there any references discussing this interesting effect?
There is nothing interesting about this.

The charge distribution at a time t before the wave reaches the detector is Q(x,t). The integral over x is Q approx 0 (but can well be of the order of e), but locally Q(x,t) is nonzero. Q(x,t) changes stochastically with time, preserving the zero mean but fluctuating via small random movements of the local charge distribution. When the electron wave begins to touch the detector, Q(x,t) increases locally a tiny amount wherever the interference pattern allows it. The total charge increases, until after the whole wave packet reached the detector, the charge has changed by -e. The stochastic process governing the local redistribution of the charge is influenced by the external field and affects the way the charge field changes. At some time, one of the pixels fires, by transferring a whole electron to the register. This is again accompanied by a local change of charge density only.

Charge current is always locally conserved, and nowhere is a sign of the spooky process you claim must have happened.
 
  • #147
A. Neumaier said:
The charge distribution at a time t before the wave reaches the detector is Q(x,t). The integral over x is Q approx 0 (but can well be of the order of e), but locally Q(x,t) is nonzero. Q(x,t) changes stochastically with time, preserving the zero mean but fluctuating via small random movements of the local charge distribution. When the electron wave begins to touch the detector, Q(x,t) increases locally a tiny amount wherever the interference pattern allows it. The total charge increases, until after the whole wave packet reached the detector, the charge has changed by -e. The stochastic process governing the local redistribution of the charge is influenced by the external field and affects the way the charge field changes. At some time, one of the pixels fires, by transferring a whole electron to the register. This is again accompanied by a local change of charge density only.

In this continuous charge model, is there an explanation for the fact that in observed systems (molecular ions or Millikan oil drops) we always see integer number of unit charges e?

Eugene.
 
  • #148
meopemuk said:
In this continuous charge model, is there an explanation for the fact that in observed systems (molecular ions or Millikan oil drops) we always see integer number of unit charges e?

Of course. Total charge is conserved and quantized in QFT, and there is a corresponding superselection rule (while there is none for particle number). Thus at microscopically large distances one can separate only integer number of charges.

Things are different for charges embedded in matter, where fractional charges may appear in quantum wires.
 
  • #149
Arnold,

I think we now agree that the field-based view (which you advocate) and the particle-based view (which I defend in my book) are two completely different ways to think about nature. I can possibly agree that both these ways have the right to exist and coexist. However, so far you wasn't able to convince me that the particle-based view has any fundamental flaws associated with it.

By the way, I should thank you again for the hint regarding IR infinities in radiative corrections. Using this idea I was able to reproduce the Uehling potential and the electron's anomalous magnetic moment in my approach. I will add this stuff to the next revision of the book. The Lamb shift is a tougher cookie. It would possibly require a full-blown Kulish-Faddeev-type infrared theory. I am working on it.

Eugene.
 
  • #150
meopemuk said:
I think we now agree that the field-based view (which you advocate) and the particle-based view (which I defend in my book) are two completely different ways to think about nature. I can possibly agree that both these ways have the right to exist and coexist. However, so far you wasn't able to convince me that the particle-based view has any fundamental flaws associated with it.
It is _fundamentally_ flawed _only_ when there are massless fields, since then your Hamiltonian is not self-adjoint (else it would generate a finite perturbation series without IR divergences).

For massive QED, your approach is basically sound, and only the weird discussion about causality you associate with it is flawed. If you want to get insight into the latter, please respond to the thread https://www.physicsforums.com/showthread.php?t=474571
 

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