BRS: Timelike Congruences. III. Evolution of the Decomposition
It might seem that timelike congruences can have arbitrarily varied expansion scalars, shear tensors, and vorticity tensors, but this is not true. It turns out that the question of which properties timelike congruences in a given Lorentzian manifold can possesses is constrained by the properties of the Riemann tensor of our manifold. Even better, the mere fact that a timelike congruence with certain properties exists can provide information about the nature of the Riemann tensor. This is very useful in gtr.
In this section, I propose to study a very natural question: how does the decomposition of a timelike congruence evolve wrt proper time as we move along the proper time parameterized curves in the congruence?
Because the quantities in the decomposition of a timelike congruence are computed using first covariant derivatives, and because in general
<br />
{\dot{Y}^{ab}}_{cde} = {Y^{ab}}_{cde;m} \, X^m<br />
(where the dot notation hides the fact that we have in mind a particular timelike unit vector field \vec{X}, the field of tangent vectors to the curves in a particular timelike congruence), to answer this question we will need to investigate the second covariant derivative of \vec{X} along itself. This is where curvature comes in: the Ricci identity says
<br />
X_{a;nb} - X_{a;bn} = X^m \, R_{ambn}<br />
or, rearranging terms,
<br />
X_{a;nb} = X_{a;bn} + X^m \, R_{ambn}<br />
Thus
<br />
\begin{array}{rcl}<br />
\dot{J}_{ab} &= & X_{a;bn} \, X^n \\ <br />
& = & X_{a;nb} \, X^n - R_{ambn} \, X^m \, X^n \\<br />
& = & X_{a;nb} \, X^n - {E\left[\vec{X}\right]}_{ab} \\<br />
& = & J_{an;b} \, X^n - {E\left[\vec{X}\right]}_{ab}<br />
\end{array}<br />
But
<br />
\begin{array}{rcl}<br />
\dot{X}_{a;b} & = & \left( J_{an} \, X^n \right)_{;b} \\<br />
& = & J_{an;b} \, X^n + J_{an} \, {X^n}_{;b} \\<br />
& = & J_{an;b} \, X^n + J_{an} \, {J^n}_{b}<br />
\end{array}<br />
so
<br />
\dot{J}_{ab} = \dot{X}_{a;b} - J_{an} \, {J^n}_b <br />
- {E\left[\vec{X}\right]}_{ab}<br />
For simplicity, let's momentarily restrict to the case of a timelike
geodesic congruence, so that we can write
<br />
J_{ab} = \frac{\theta}{3} \, h_{ab} + \sigma_{ab} + \omega_{ab}<br />
where I am dropping the brackets which reminded us that all quantities appearing in this decomposition are defined in terms of a particular congruence. Expanding J_{an} \, {J^n}_b and collecting terms gives
<br />
J_{an} \, {J^n}_b<br />
= \frac{\theta^2}{9} \, h_{ab}<br />
\, + \, \frac{2 \, \theta}{3} <br />
\; \left( \sigma_{ab} + \omega_{ab} \right)<br />
\, + \, \sigma_{am} \, {\sigma^m}_b<br />
\, + \, \omega_{am} \, {\omega^m}_b<br />
\, + \, \sigma_{am} \, {\omega^m}_b<br />
\, + \, \omega_{am} \, {\sigma^m}_b<br />
The trace is
<br />
\begin{array}{rcl}<br />
J_{am} \, J^{ma} & = & \frac{\theta^2}{3}<br />
\, + \, \sigma_{am} \, \sigma^{ma}<br />
\, + \, \omega_{am} \, \omega^{ma}<br />
\, + \, \sigma_{am} \, \omega^{ma}<br />
\, + \, \omega_{am} \, \sigma^{ma} \\<br />
& = & \frac{\theta^2}{3}<br />
\, + \, \sigma_{am} \, \sigma^{am}<br />
\, - \, \omega_{am} \, \omega^{am}<br />
\, - \, \sigma_{am} \, \omega^{am}<br />
\, + \, \omega_{am} \, \sigma^{am} \\<br />
& = & \frac{\theta^2}{3} + \sigma^2 - \omega^2<br />
\end{array}<br />
where we have used the symmetry and tracelessness of the shear tensor and the antisymmetry of the vorticity tensor, and where
<br />
\begin{array}{rcl}<br />
\sigma^2 & = & \sigma_{mn} \, \sigma^{mn} \\<br />
\omega^2 & = & \omega_{mn} \, \omega^{mn} <br />
\end{array}<br />
are
quadratic invariants of the shear and vorticity tensors of our congruence. (Warning: some authors introduce a factor of 1/2 into these defintions!) Notice that because these are invariants of tensors which live in a three dimensional euclidean inner product space, they are
non-negative.
Thus, we have shown that for timelike geodesic congruences,
<br />
\dot{\theta} = <br />
- \, \frac{\theta^2}{3} \, - \, \sigma^2 \, + \, \omega^2<br />
\, - \, {E_m}^{m}<br />
More generally, restoring the acceleration terms, you can verify that we obtain
<br />
\dot{\theta} = <br />
- \, \frac{\theta^2}{3} \, - \, \sigma^2 \, + \, \omega^2<br />
\, - \, {E_m}^{m} + {\dot{X}^m}_{;m}<br />
where the last term is the covariant divergence of the acceleration vector of our timelike unit vector field. This is known as the
Raychaudhuri formula. Each term in this formula is a scalar invariant partially characterizing our congruence, which has a geometric meaning independent of which coordinate chart we use. This formula is true and makes sense independently of gtr, and even independently of physics, but it turns out that in the context gtr, each term in the Raychaudhuri formula also has a physical meaning.
When studying the Raychaudhuri formula, it is useful to notice that
<br />
\begin{array}{rcl}<br />
{E^a}_a & = & {R^a}_{man} X^m X^n \\<br />
& = & R_{mn} \, X^m \, X^n \\<br />
& = & \left( G_{mn} - \frac{G}{2} \, g_{mn} \right) \, X^m X^n \\<br />
& = & 8 \pi \, \left( T_{mn} - \frac{T}{2} \, g_{mn} \right) \, X^m X^n<br />
\end{array}<br />
Thus, the trace of the tidal tensor is
independent of the Weyl curvature tensor! (Note well: the tidal tensor is the
electroriemann tensor, not the
electroweyl tensor!)
Now we can easily obtain expressions for the trace of tidal tensor (electroriemann tensor) corresponding to various types of matter tensors. In particular:
- in a vacuum region, the trace of the electroriemann tensor vanishes,
- in an electrovacuum region, taking a congruence appropriately aligned with the field (usually there will be many which work),
<br />
{E^m}_m = 8 \pi \, \epsilon<br />
where \epsilon is the energy density of the EM field.
- in a perfect fluid region,
<br />
{E^m}_m = 4 \pi \, \left( \rho + 3 p \right)<br />
where \rho is the mass-energy density and p is the pressure.
Indeed, if we know the form of the matter tensor, we can usually say more. For example, consider the congruence of world lines of the fluid elements in a perfect fluid. The matter tensor is
<br />
T^{ab} = ( \rho + p ) \, X^a \, X^b + p \, g^{ab}<br />
and the identity {T^{ab}}_{;b} = 0 gives some useful relations:
<br />
\begin{array}{rcl}<br />
\theta & = & {X^m}_{;m} = \frac{-\dot{\rho}}{\rho + p} \\<br />
\dot{X}^a & = & \frac{-h^{am} \, p_{;m}}{\rho + p}<br />
\end{array}<br />
The first equation says that the expansion scalar is positive at some event iff the density is decreasing, as measured by an observer comoving with the fluid there, and vanishes iff the density is momentarily constant there. The second equation says that the acceleration vector is the projection to the orthogonal hyperplane element of the negative of the gradient of the pressure, multiplied by a non-negative scalar.
Summing up: the evolution of the expansion scalar of a timelike congruence is given by
- in a vacuum region,
<br />
\dot{\theta} = <br />
{\dot{X}^m}_{;m}<br />
\, + \, \omega^2<br />
\, - \, \frac{\theta^2}{3} \, - \, \sigma^2<br />
- in an electrovacuum region, for some congruence which is suitably aligned with the field,
<br />
\dot{\theta} = <br />
{\dot{X}^m}_{;m}<br />
\, + \, \omega^2<br />
\, - \, \frac{\theta^2}{3} \, - \, \sigma^2<br />
\, - \, 8 \pi \, \epsilon<br />
- in a region filled with perfect fluid (and no other matter or nongravitational fields), for the congruence of world lines of the fluid elements
<br />
\dot{\theta} = <br />
{\dot{X}^m}_{;m}<br />
\, + \, \omega^2<br />
\, - \, \frac{\theta^2}{3} \, - \, \sigma^2<br />
\, - \, 4 \pi \, \left( \rho + 3 p \right)<br />
Let us consider what the last formula says about the timelike congruence defined by the world lines of the matter in a fluid ball. We see that nonzero vorticity tensor--- which we will see is associated with "swirling"---
opposes gravitational collapse (via "centrifugal force"), while nonzero expansion scalar--- of
either sign--- and nonzero shear tensor both tend to
promote gravitational collapse. Furthermore, both density
and pressure tend to
promote gravitational collapse, unless this is halted by hydrostatic forces.
In a static spherically symmetric perfect fluid ball at equilibrium, Raychaudhuri's formula reduces to
<br />
{\dot{X}^m}_{;m}<br />
= 4 \pi \, \left( \rho + 3 p \right)<br />
In a static spherically symmetric elastic body at equilibrium, we might have something like
<br />
{\dot{X}^m}_{;m}<br />
= 4 \pi \, \left( \rho + p_{\hbox{rad}} + 2 p_{\perp} \right)<br />
In a
stationary rotating perfect fluid ball, both the vorticity and shear tensors are generally nonzero (nonzero shear arises from angular velocities varying with position), and Raychaudhuri's formula becomes
<br />
{\dot{X}^m}_{;m}<br />
= 4 \pi \, \left( \rho + 3 p \right)<br />
\, + \, \sigma^2 \, - \, \omega^2<br />
In the special case of the congruence of world lines of the dust particles in a
dust solution (a perfect fluid solution with vanishing pressure), the acceleration vanishes (no forces act on the dust particles), and we may write
<br />
\dot{\theta} = <br />
\omega^2<br />
\, - \, \frac{\theta^2}{3} \, - \, \sigma^2<br />
\, - \, 4 \pi \, \rho<br />
This shows clearly that only nonzero vorticity can prevent a dust cloud from collapsing. In the case of swirling dust clouds, we'll see that nonzero shear is associated with "nonrigid swirling", and this promotes collapse whenever it occurs. Furthermore, for a dust solution, the expansion scalar of the congruence of world lines of the dust particles is the logarithmic derivative of the density wrt proper time
<br />
\theta = -\dot{\rho}/\rho<br />
(Warning: the assumption of zero pressure is only good until it fails; exact dust solution models of collapse tend to develop caustics in the congruence of world lines of the dust particles, i.e. curves or sheets where the density diverges to plus infinity and expansion scalar diverges to minus infinity, and physically we should expect nonzero pressure to occur at these places! At present there is quite a bit of interesting work on finding exact solutions of the Einstein-Vlasov equation which models dust "probabilistically"; this turns out to neatly evade many of the problems with dust solutions.)
Returning to our expression for \dot{J}_{ab}, we can also take the symmetric and antisymmetric parts, which gives us formulas for the proper time evolution of the expansion tensor and vorticity tensor, and we then obtain an expression for the proper time evolution of the shear tensor. Then it turns out that the time evolution of the vorticity tensor does not depend upon the curvature tensor, but the time evolution of the shear tensor depends upon the tidal tensor.
To find the evolution of the shear and vorticity tensors, it helps to rewrite everything in terms of linear operators. In
<br />
\dot{J^a}_b = {\dot{X}^a}_b - {J^a}_m \, {J^m}_b - {E^a}_b<br />
for simplicity let us first consider the case where \vec{X} is a timelike
geodesic congruence, so that we may write
<br />
{J^a}_b = \frac{\theta}{3} \, {h^a}_b + {\sigma^a}_b <br />
+ {\omega^a}_b<br />
Multiplying out and collecting terms as before we obtain
<br />
{\dot{J}^a}_{ \; b}<br />
= - \, \frac{\theta^2}{9} \, {h^a}_b<br />
\, - \, \frac{2 \, \theta}{3} <br />
\; \left( {\sigma^a}_b + {\omega^a}_b \right)<br />
\, - \, {\sigma^a}_m \, {\sigma^m}_b<br />
\, - \, {\omega^a}_m \, {\omega^m}_b<br />
\, - \, {\sigma^a}_m \, {\omega^m}_b<br />
\, - \, {\omega^a}_m \, {\sigma^m}_b<br />
\, - \, {E^a}_b<br />
In terms of matrix algebra, we may write
<br />
\Sigma = {\sigma^a}_b, \; \;<br />
\Omega = {\omega^a}_b, \; \;<br />
{\cal E} = {E^a}_b, \; \;<br />
{\cal J} = {J^a}_b = {\dot{X}^a}_{\; ;b}<br />
which are respectively symmetric traceless, antisymmetric, symmetric (but not traceless, in general), and "none of the above". Then
<br />
{\cal \dot{J}} = - \, \frac{\theta^2}{9} \, I <br />
\, - \, \frac{2\theta}{3} \; \left( \Sigma + \Omega \right)<br />
\, - \, \left( \Sigma^2 + \Omega^2 \right)<br />
\, - \, \left( \Sigma \, \Omega + \Omega \, \Sigma \right)<br />
\, - \, {\cal E}<br />
Now you can check that for any 3x3 symmetric and antisymmetric matrices A,B, it is true that A^2+B^2 is symmetric while AB + BA is antisymmetric. Therefore the symmetric part of our matrix expression is
<br />
- \, \frac{\theta^2}{9} \, I <br />
\, - \, \frac{2\theta}{3} \, \Sigma<br />
\, - \, \left( \Sigma^2 + \Omega^2 + {\cal E} \right)<br />
while the antisymmetric part is
<br />
- \, \frac{2\theta}{3} \; \Omega<br />
\, - \, \left( \Sigma \, \Omega + \Omega \, \Sigma \right)<br />
From the first we see again that the scalar part is
<br />
- \, \left( \frac{\theta^2}{9} + \operatorname{tr} <br />
\left( \Sigma^2 + \Omega^2 + {\cal E} \right) \right) \; I<br />
And the traceless symmetric part is
<br />
- \, \frac{2\theta}{3} \, \Sigma<br />
\, - \, \left( \Sigma^2 + \Omega^2 + {\cal E} \right)<br />
\, + \, \frac{ \operatorname{tr} <br />
\left( \Sigma^2 + \Omega^2 + {\cal E} \right)}{3} \, I<br />
Thus, for timelike geodesic congruences,
<br />
\begin{array}{rcl}<br />
{\dot{\sigma}^a}_{\; b} & = &<br />
- \, \frac{2 \theta^2}{3} \; {\sigma^a}_b<br />
\, - \, {\sigma^a}_m \, {\sigma^m}_b<br />
\, - \, {\omega^a}_m \, {\omega^m}_b<br />
\, - \, {E^a}_b<br />
\, + \, \frac{\sigma^2-\omega^2 + {E^m}_m}{3} \; {h^a}_b<br />
\\<br />
{\dot{\omega}^a}_{\; b} & = &<br />
- \, \frac{2 \theta^2}{3} \; {\omega^a}_b<br />
\, - \, {\sigma^a}_m \, {\omega^m}_b<br />
\, - \, {\omega^a}_m \, {\sigma^m}_b<br />
\end{array}<br />
Gathering results,
the evolution equations for the kinematic decomposition are:
<br />
\begin{array}{rcl}<br />
\dot{\theta} & = & <br />
- \, \frac{\theta^2}{3} <br />
\, - \, \sigma^2 <br />
\, + \, \omega^2<br />
\, - \, {E_m}^{m} \\<br />
\dot{\sigma}_{ab} & = &<br />
- \, \frac{2 \theta^2}{3} \; \sigma_{ab}<br />
\, - \, \sigma_{am} \, {\sigma^m}_b<br />
\, - \, \omega_{am} \, {\omega^m}_b<br />
\, - \, E_{ab}<br />
\, + \, \frac{\sigma^2-\omega^2 + {E^m}_m}{3} \; h_{ab}<br />
\\<br />
\dot{\omega}_{ab} & = &<br />
- \, \frac{2 \theta^2}{3} \; \omega_{ab}<br />
\, - \, \sigma_{am} \, {\omega^m}_b<br />
\, - \, \omega_{am} \, {\sigma^m}_b<br />
\end{array}<br />
The last equation implies that if the vorticity tensor vanishes at any event on a timelike geodesic curve, it vanishes all along that geodesic. Recalling the theorem of Frobenius, this means that if some "tubular bundle" of curves belonging to a timelike geodesic congruence has even one orthogonal hyperslice, it continues to have orthogonal hyperslices along the curves in the bundle. We'll see later that this means that a small body which is initially nonrotating (in the sense of zero vorticity) cannot later start to rotate (in the sense of nonzero vorticity) unless nongravitational forces act.
In a dust region, using {E^m}_m = 4 \pi \, \rho we can write the
evolution equations for the kinematic decomposition of the congruence of world lines of the dust particles as:
<br />
\begin{array}{rcl}<br />
\dot{\theta} & = & <br />
- \, \frac{\theta^2}{3} <br />
\, - \, \sigma^2 <br />
\, + \, \omega^2<br />
\, - \, 4 \pi \, \rho \\<br />
\dot{\sigma}_{ab} & = &<br />
- \, \frac{2 \theta^2}{3} \; \sigma_{ab}<br />
\, - \, \sigma_{am} \, {\sigma^m}_b<br />
\, - \, \omega_{am} \, {\omega^m}_b<br />
\, - \, E_{ab}<br />
\, + \, \frac{\sigma^2-\omega^2 + 4 \pi \, \rho}{3} \; h_{ab}<br />
\\<br />
\dot{\omega}_{ab} & = &<br />
- \, \frac{2 \theta^2}{3} \; \omega_{ab}<br />
\, - \, \sigma_{am} \, {\omega^m}_b<br />
\, - \, \omega_{am} \, {\sigma^m}_b<br />
\end{array}<br />
Suppose the dust cloud is initially stationary, so that the terms appearing on the right hand sides of all three equations sum to zero. In particular, the dust must have just the right vorticity to balance the effects of nonzero shear on the expansion scalar. Bye and bye, along comes a gravitational plane wave, which adds a traceless perturbation to the tidal tensor. This causes \dot{\sigma}_{ab} to become nonzero, which causes \sigma^2 to become positive, which causes the proper time derivative of the expansion scalar to become negative, which initiates a collapse scenario. As \theta = -\dot{\rho}/\rho decreases from whatever value it had initially (constant along the initial segment of each world line), eventually it becomes negative. Since \theta = -\dot{\rho}/\rho implies
<br />
\rho = \rho_0 \, \exp \left( -\int \theta ds \right)<br />
where the integral is taken wrt proper time along a world line, this implies that
the density starts to increase superexponentially, which in turn cases superexponential decrease in the proper time derivative of the expansion scalar. Also, \theta^2 increases, which only makes things worse: the density increases faster and faster as the expansion scalar continues to decrease faster and faster. Only if the \sigma_{am} \, {\omega^m}_b + \omega_{am} \, {\sigma^m}_b term quickly creates just enough vorticity to rebalance the equation for proper time derivative of the expansion scalar can the cloud avoid gravitational collapse. This suggests why cosmologists think gravitational waves may have played a part in structure formation in the early universe.
Ellis showed that a shear-free dust must have either vanishing expansion scalar or vanishing vorticity. In the first case, we have constant vorticity tensor ("rigidly rotating dust"); in the second case, we have isotropic expansion tensor (e.g. FRW dust or Milne congruence in Minkowski vacuum). Thus, shear-free dusts are rare.
Returning to the general case, when we include the acceleration terms, we find:
<br />
\dot{J}_{ab} = <br />
\dot{X}_{a;b} <br />
\, + \, \frac{2 \theta}{3} \, \dot{X}_a \, X_b <br />
\, + \, \hbox{old} \; \hbox{stuff}<br />
We can compute the scalar part, traceless symmetric part, and antisymmetric part of the new terms independently of the others (since this is just linear algebra). Carrying out this procedure, we find that
the evolution equations for the decomposition of a general timelike congruence are:
<br />
\begin{array}{rcl}<br />
\dot{\theta} & = & <br />
- \, \frac{\theta^2}{3} <br />
\, - \, \sigma^2 <br />
\, + \, \omega^2<br />
\, - \, {E^m}_{m} <br />
\, + \, {\dot{X}^m}_{ \; ;m} \\<br />
\dot{\sigma}_{ab} & = &<br />
- \, \frac{2 \theta^2}{3} \; \sigma_{ab}<br />
\, - \, \sigma_{am} \, {\sigma^m}_b<br />
\, - \, \omega_{am} \, {\omega^m}_b<br />
\, - \, E_{ab}<br />
\, + \, \frac{\sigma^2-\omega^2 + {E^m}_m - {\dot{X}^m}_{;m}}{3} \; h_{ab}<br />
\, + \, <br />
\frac{\theta}{3} \;<br />
\left( \dot{X}_a \, X_b + \dot{X}_b \, X_a \right)<br />
\, + \, \dot{X}_{(a;b)}<br />
\\<br />
\dot{\omega}_{ab} & = &<br />
- \, \frac{2 \theta^2}{3} \; \omega_{ab}<br />
\, - \, \sigma_{am} \, {\omega^m}_b<br />
\, - \, \omega_{am} \, {\sigma^m}_b<br />
\, + \, \frac{\theta}{3} \;<br />
\left( \dot{X}_a \, X_b - \dot{X}_b \, X_a \right)<br />
\, + \, \dot{X}_{[a ;b]}<br />
\end{array}<br />
In these computations, quite a few terms drop out because for a timelike
unit vector field \vec{X}, the acceleration vector field is everywhere orthogonal to tangent vector field:
<br />
\dot{X}^m \, X_m = 0<br />
You might think that only a mother could love the evolution equations I just wrote down. However, in the case of a perfect fluid, we can rewrite many of the terms in
the evolution equations for the congruence of world lines of the fluid elements, in order to obtain physical insight into how the fluid evolves.
A generalization of Ellis's theorem would state that a shearfree isentropic perfect fluid must have either vanishing vorticity (e.g., FRW fluid) or vanishing expansion scalar ("rigidly rotating" fluid). (An isentropic fluid has an equation of state giving pressure as a function of density.) AFAIK, deciding whether this is true in general is an open problem. AFAIK, all known perfect fluid solutions are consistent with this conjecture.