What Are the Magnitudes and Direction Angles of the Vector R=2i + j + 3k?

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The discussion revolves around finding the magnitude and direction angles of the vector R=2i + j + 3k. To calculate the magnitude, the formula √(x² + y² + z²) is used, where x, y, and z are the components of the vector. Direction angles can be determined by finding a unit vector, which involves using the direction cosines related to the angles the vector makes with the x, y, and z axes. Participants emphasize the importance of showing work before seeking help and clarify misconceptions about vector magnitudes. Overall, the thread highlights the need for a foundational understanding of vector components and their properties.
gearstrike
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how to solve this question??

A vector is given by R=2i + j + 3k.
find (a) the magnitude of the x,y,z components,
(b) the angels between R and the x,y and z axes..
 
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How much do you know about vectors? These questions are fairly basic.
 


punderq arunburg...m asking u to do dat question...not to comment my question...u little funky...challenge u to answer my question ...
 


Please read the forum rules. You are expected to show your work before anyone can help. And no, your questions are not "challenging" at all.
 


gearstrike, we only help after you've shown us some attempt at trying to solve it yourself.

In your class or textbook, haven't they discussed the components of a vector? And something (anything) about angles & vectors?
 


gearstrike said:
punderq arunburg...m asking u to do dat question...not to comment my question...u little funky...challenge u to answer my question ...
lmao! Funny talking little funky :p
 


im sory guys,
im really don't know about this question..
basicly,im bad in basic..can you guys help me.?
 


Well, to start off, what do you understand by the "magnitude of the x,y,z components"? And for the second, what have you learned about the dot product that you can apply here?
 


ermm,
what i know abaout magnitude x,y and z is equal to = i + j + k.
 
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gearstrike said:
ermm,
what i know abaout magnitude x,y and z is equal to = i + j + k.
That makes no sense at all! The magnitude of a vector is its length- a number, not a vector. The magnitude of the vector x\vec{i}+ y\vec{j}+ z\vec{k} is \sqrt{x^2+ y^2+ z^2}.

To find the "direction angles", the angles a vector makes with the x, y, and z axes, you find a unit vector in that direction. The components of a unit vector are the "direction cosines": a unit vector is always of the form cos(\theta)\vec{i}+ cos(\phi)\vec{j}+ cos(\psi)\vec{k} where \theta, \phi, and \psi are the angles the vector makes with the x, y, and z axes respectively.
 
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