What are the optimal dimensions for a non-oversized carton with maximum volume?

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SUMMARY

The discussion focuses on determining the optimal dimensions for a non-oversized carton with maximum volume, adhering to postal regulations that define oversized cartons based on height and girth. The key equations established are h + 4x = 108 for girth and V = x²h for volume, where x represents the side length of the square base and h is the height. The calculations reveal that the optimal dimensions are x = 13.5 inches and h = 54 inches, ensuring the carton remains within the specified limits while maximizing volume.

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  • Understanding of basic algebra and equations
  • Knowledge of volume calculations for geometric shapes
  • Familiarity with postal regulations regarding carton dimensions
  • Ability to differentiate between units of measurement (square inches vs. cubic inches)
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  • Explore the concept of girth in packaging design
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This discussion is beneficial for mathematicians, packaging engineers, logistics professionals, and anyone involved in shipping and packaging design who needs to optimize carton dimensions for efficiency and compliance.

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Homework Statement



According to postal regulations, a carton is classified as "over-sized" if the sum of its height and girth (the perimeter of its base) exceeds 108 in. Find the dimensions of a carton with square base that is not oversized and has maximum volume.

Homework Equations





The Attempt at a Solution



I set up the equations.

h + 4x = 108
4x(h)=volume
h=108-4x
432x-16x^2=volume
432-32x=Dv/dx
432=32x
x=13.5
h=54
 
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physstudent1 said:
I set up the equations.

h + 4x = 108
4x(h)=volume

Your equation for the girth seems to agree with the definition you were given.

But your volume equation cannot be correct, because the left hand side will only have units of square inches, while volume is in cubic inches. If the base of this box is a square, what must its volume be?
 
oh, should the equation for volume be

x^2(h)=v
 

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