What Are the Partial Pressures and Total Pressure in a Reaction Mixture?

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The discussion centers on calculating the partial pressures and total pressure of a reaction mixture containing hydrogen and nitrogen gases. Initially, a vessel holds 2.0 moles of H2 and 1.0 mole of N2 at 273.15K. After the complete reaction of H2 with N2 to form NH3, the total pressure can be determined using the ideal gas law, PV = nRT, with the total moles of gas in the final mixture. The mole fractions of each gas are calculated to find their respective partial pressures. The solution aligns with the book's answer, confirming the calculations.
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[SOLVED] PCHEM/Partial Pressures Question

Problem Statement:
A vessel of volume 22.4dm^{}3 contains 2.0 mol H_{}2 and 1.0 mol of N_{}2 at 273.15K initially. All the H_{}2reacted with sufficient N_{}2 to form NH_{}3. Calculate the partial pressures and the total pressure of the final mixture.

Variables and Magnitudes:
V = 22.4dm^{}3
T = 273.15K
n_{}H_{}2= 2.0 mol
n_{}N_{}2= 1.0 mol

First Attempt:
2H_{}2+N_{}2\rightarrowNH_{}3
It takes 1.5 mol of H_{}2 to make 1 mol of NH_{}3 so I was thinking that I should say that:

p_{}H_{}2 = p_{}total*X_{}H_{}2 = ?

We would need to calculate the total pressure first for this.

I need a place to start this problem. I just can't put my finger on it.
 
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After working on the problem some more; I found that there is a simple way to do the problem. Simply find the mole fractions with the number of moles given and calculate the total pressure with PV = nRT for 3 moles, and 22.4dm^3.

Not much more to it than that. The solution in the book matches up.
 
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