What are the steps for graphically solving a system of equations?

AI Thread Summary
To solve the system of equations graphically, the first equation yields an intersection point at (1, -1), confirmed by substituting x into both equations. For the second equation, estimated intersection points are (+/- 3.7, +/- 1.8). Users are encouraged to substitute graphically obtained points back into the original equations for verification. To solve algebraically, set the two expressions for y equal to each other, resulting in a quadratic equation that can be solved for x. The discussion emphasizes the importance of checking solutions and understanding the relationship between graphical and algebraic methods.
duki
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Homework Statement



Solve the system of equations graphically.

Homework Equations



1)
4x - y = 5
y = 4 - 5x^2


2)
2x^2 + y^2 = 33
x^2 - y^2 = 12

The Attempt at a Solution



The answers I got for the intersecting points are:
1)
(1, -1)

And

2)
(+/- 3.7, +/- 1.8)

These are estimates from graphing, but I'm not sure if I'm close... I don't know how to check myself algebraically yet... =/
 
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You should be able to at least substitute your graphically-obtained points into the equations.
 
I did that mostly...

but for the equations like y = 4 - 5x^2, is that the same as saying:

y = 4 - 5(-1)^2?
or would it bet
y = 4 - 5(-1^2)?

for that particular equations here are my points:

x...| y
0 ....4
+/-.89 ...0
+/- 1 ...-1
+/- 2 ...-3
 
for your first problem you have found a possible solution at (1,-1).

Your equations are:
y= 4x -5
and
y= 4 - 5 x 2

Plugging x = 1 into each of these yields:

y = 4(1) -5 = -1

Thus your point is a solution for this equation.

Repeat for the second equation.

y = 4 - 5(-1) 2 = 4 -5 = -1

Thus your solution works in both equations and is an intersection point.

Do the same thing with your second problem.
 
groovy, good to know I'm on the right path...

could you show me how to solve algebraically (#1)? If you could give me a start I'll work on it and let you know where I get...
 
In my last post I expressed both equatons of your first problem as y expressed in terms of x. Eliminate y by setting them equal, then solve for x.

y= 4x -5
y = 4 - 5x 2
4x -5 = 4 - 5x 2
5x 2 + 4x - 9 = 0

Can you finish?
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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