What are the steps to manipulate this equation and solve for r2?

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To solve for r2 in the equation (n-1)((1/r1^3)-(1/r2^3))(y^4/8) = (y^4/32f^3), first eliminate y^4 by dividing both sides by it. Next, combine the fractions involving r1 and r2 on the left side and substitute r1 with f. Expand the left side to isolate terms containing r2. Finally, divide both sides by the coefficient of r2 to derive the formula r2 = ((4n-4)/(4n-5))^(1/3)) * f. This process allows for a clear path to the desired solution.
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I need help gettin from

(n-1)((1/r1^3)-(1/r2^3))(y^4/8) = (y^4/32f^3)

r1 and r2 have the 1 and 2 and subscript and are not numbers.

Question states r1 = f

Supposed to end up with

r2 = ((4n-4)/(4n-5))^(1/3)) * f

Can anyone show me the steps?!
 
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razmataz said:
I need help gettin from

(n-1)((1/r1^3)-(1/r2^3))(y^4/8) = (y^4/32f^3)

r1 and r2 have the 1 and 2 and subscript and are not numbers.

Question states r1 = f

Supposed to end up with

r2 = ((4n-4)/(4n-5))^(1/3)) * f

Can anyone show me the steps?!

Since y4 appears on both sides, you can eliminate it by dividing both sides by y4 (and assuming that y \neq 0).

Then, combine the two fractions in r1 and r2 on the left side.
Then, replace r1 by f.

Then expand everything on the left side. After that, isolate all terms that involve r2 and divide both sides by the coefficient of r2.
 
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