What are the times when a pellet reaches 25 meters above its initial height?

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A pellet is fired upward with an initial velocity of 25 m/s, and the goal is to determine the times it reaches 25 meters above its initial height. The equation derived is 25 = 25t - 4.91t^2, which can be solved by factoring or completing the square. Since the quadratic formula is not permitted for the student, the discussion focuses on alternative methods to find the two times. The final times calculated are approximately 1.37 seconds and 3.74 seconds. This problem illustrates the application of kinematic equations in projectile motion.
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Homework Statement


A pellet is fired upward with an initial velocity of 25 m/s. At what times in the pellet 25 meters above its fired height


Homework Equations


S=ut+1/2at^2 I got it down to,
Displacement(s)=25m
U(initial velocity)=25 m/s
and a=acceleration due to gravity -9.81
I got 25=25t+1/2(-9.81)(t^2)
then 25=25t+-4.91t^2 and I am stumped

The Attempt at a Solution



I tried dividing both sides by 25t, leaving
1/t=-4.91t^2, but I really have no clue.
I can't use the quadratic formula and I need 2 times. Any hints would be very nice! Thank you.
 
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I'm a little bit confused, are you not allowed to use the quadratic formula for this problem? The quadratic formula is the perfect way to solve for those two times.
 
kiwikahuna said:
I'm a little bit confused, are you not allowed to use the quadratic formula for this problem? The quadratic formula is the perfect way to solve for those two times.
Well I am in grade 10, and we haven't learned it yet, so it is off limits. Sorry for the confusion
 
In that case, you should find the final velocity of this projectile motion. After you find the final velocity, you can find the times using the definition of acceleration.
 
Well, let's start with what you arrived at:

25=25t+-4.91t^2

Now just factor this equation to find the values of t. You probably know the method of completing the squares, that is :

-4.9t^2 + 25t = 25

Dividing through whatever is multiplied on the square term

-t^2 + (25/4.9)t = 25/4.9

making the squared term positive

t^2 - (25/4.9)t = -25/4.9


Half the x coefficient (-25/4.9) -> (-25/9.8) and squaring it: (625/96.04) then adding this to both sides:

t^2 - (25/4.9)t + 625/96.04 = -25/4.9 + 625/96.04

then you know:

(t - 25/9.8)^2 = (625(4.9) - 25(96.04))/(4.9)(96.04)

simplifying:

(t-25/9.8)^2 = 661.5/470.596

Thus you know that

t - 25/9.8 = +/- sqrt (661.5/470.596)

as both the negative and positive numbers make a square positive number.

and thus your answers:

t = 25/9.8 +/- sqrt (661.5/470.596)

and using your trusty calculator you know now :

t = 3.736627555 (for the +)
and
t = 1.365413261 (for the -)
 
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