What are the values of x and y for the complex number z=\sqrt{3+4i}?

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SUMMARY

The discussion focuses on determining the values of x and y for the complex number z = √(3 + 4i). Participants emphasize the importance of squaring both sides of the equation and equating the real and imaginary parts to solve for x and y. The conversation highlights that there are two square roots for the complex number, confirming the existence of two solutions. Additionally, an alternative method using polar form and de Moivre's formula is mentioned, although the direct approach is favored for its simplicity.

PREREQUISITES
  • Understanding of complex numbers and their properties
  • Familiarity with squaring equations
  • Knowledge of equating real and imaginary parts
  • Basic understanding of polar coordinates and de Moivre's theorem
NEXT STEPS
  • Learn how to convert complex numbers to polar form
  • Study de Moivre's theorem for complex number operations
  • Explore the properties of square roots of complex numbers
  • Practice solving equations involving complex variables
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Students and educators in mathematics, particularly those studying complex numbers, as well as anyone looking to enhance their problem-solving skills in algebra and complex analysis.

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z=x+yi determine the values of x and y such that z=\sqrt{3+4i}
I'm not even sure where to start with this one, so any help would be greatly appreciated
 
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So basically the question you are given is find x and y where
x+yi=\sqrt{3+4i}.
Start off by squaring both sides, then go about solving for x and y. When solving variables with complex numbers, you usually equate the real and imaginary parts of both sides. In other words, if you have x+iy=u+iv, then x=u and y=v. This should get you going. Let us know if you are still stuck.
 
In other words, find the square root of 3+4i. Of course, there are two square roots - the problem said "values"- so n!kofeyn's equations will have two solutions. You could also do this problem by converting to "polar" form and applying deMoivre's formula. That was my first thought but n!kofeyn's idea is simpler and more straightforward.
 
Awesome. I've got it now. Thanks for your help.
 
No problem.
 

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