Chemistry What Are the Wavenumbers for the First Three Rotational Transitions of CO?

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The discussion focuses on calculating the wavenumbers for the first three rotational transitions of carbon monoxide (CO) using specific equations related to rotational spectroscopy. The bond length of CO is given as 1.128 Å, and participants discuss the necessary equations, including the moment of inertia and rotational constant. Initial calculations for the reduced mass and moment of inertia are provided, leading to a calculated value for the rotational constant. However, there is confusion about applying the energy transition equation to find the wavenumbers for the first three transitions. Clarification is sought on how to effectively use the derived equations to obtain the desired values.
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Homework Statement


The bond length of CO is 1.128 Å. At what wavenumbers do the first three rotational transitions appear


Homework Equations


μ= (m1m2/m1+m2)
I = μr0^2
B= h/(8∏^2)IbC
ΔE = 2B (J+1)


The Attempt at a Solution



For the first equation I got

(12 x 16) / 28 = [(6.857 /1000)/ avagadro number] = 1.138 x 10^-26

For the second equation I got

(1.138 x 10^-26) x (1.128 x 10^-10)^2 = 1.44 x 10^-46 kg/m^2

For the third equation I got

planck's constant / [(8∏^2) x (1.44 x 10^-46 ) x (speed of light)] = 1.93cm^-1



I honestly don't know what to do after this please help
really appreciated and thank you very much
 
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You're doing fine. What about the fourth equation you listed?
 
DrClaude said:
You're doing fine. What about the fourth equation you listed?

Thats the problem, I know the answer is in that equation but I just do not know how to use it to get the values for the first 3 rotational energy levels. Just don't know to tackle that equation.Thanx for the reply
 
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