What can we determine about the electric field lines from two charges Q1 and Q2?

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SUMMARY

The discussion centers on the analysis of electric field lines generated by two charges, Q1 and Q2. Participants conclude that both charges cannot have the same sign, as indicated by the behavior of the electric field lines. It is established that the electric field can be zero at point P2 due to the opposing nature of the fields from the two charges, while at point P1, the fields add up. The application of Gauss's law is referenced to support these conclusions.

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  • Understanding of electric field lines and their behavior
  • Knowledge of Gauss's law in electrostatics
  • Familiarity with the concepts of positive and negative charges
  • Basic principles of vector addition in physics
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  • Study the implications of Gauss's law in electrostatics
  • Learn about the superposition principle for electric fields
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jra_1574
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Hello Everyone!
i need some guide and hints about this...
Here is the link for the picture...

aaaaaaaa.jpg


From the figure, the electric Field lines arising from two charges Q1 and Q2 are shown. From this drawing we can see that
A) The electric field could be zero at P2
B) Both Q1 and Q2 have the same sign
C) |Q1|>|Q2|
D) the electric field could be zero at P1
E) none of these is true


Something is telling me that B is not true... why?
the lines go from one to the other, if they were from the same sign the lines would go apart from one another...now C... we can't tell because we don't know which one is proton and which is the electron. Choice E i don't think so..
So it must be either A or D, but i don't know which one and why...
can anyone help me here please?

Thanks!
 
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I agree, B is not true. If the system contained a net charge- then there would be field lines that 'escape' from the 2 charges, whereas you can see that every field line is reabsorbed (Gauss's law).
 
can anyone give me a hint?
 
Assume one of them to be positive and the other, negative (since B is incorrect and none of them is zero charged). At P1 their fields add up, while at P2 they oppose each other. So, for some point lying in the region of P2, E will be zero.
 
Thanks for your Help!
I really appreciate it
 

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