What Causes the Change in Spin State from Fe(bipy)3 to Fe(bipy)2(H2O)2?

Thread starter silimay
Start date Apr 19, 2009

AI Thread Summary

The discussion centers on the differences in spin states of iron complexes, specifically Fe(bipy)3 being low spin and Fe(bipy)2(H2O) being high spin. The key point is the influence of ligand field strength on the spin state of the complexes. High spin complexes typically occur when the ligand field is weak, allowing for unpaired electrons, while low spin complexes arise from strong field ligands that promote pairing of electrons in the lower energy d orbitals. The addition of two water ligands to Fe(bipy)2 significantly alters the ligand field strength, leading to a substantial change in the crystal field splitting energy (10Dq). This change in 10Dq is crucial as it determines whether the electrons will remain unpaired or pair up, thus affecting the overall spin state of the complex. The discussion emphasizes the importance of ligand types and their geometric arrangement in influencing the electronic properties of metal complexes.

Apr 19, 2009

silimay

Why is Fe(bipy)3 low spin, whereas Fe(bipy)2(H2O) high spin?

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Apr 20, 2009

Borek

Mentor

Common, that's the most basic question, it must be covered in your book. Start with a general question - why are some complexes high spin whereas others are low spin? What does the spin tell about the d orbitals in the complexed metal?

Apr 22, 2009

chemisttree

Science Advisor

Homework Helper

Gold Member

The real question is, "Why does the addition of 2 water ligands change the value of 10Dq so much?"

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