What creates a partial vacuum when a fan is in motion?

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A spinning fan creates a partial vacuum by pushing air molecules away, resulting in lower pressure on the intake side compared to ambient pressure. This occurs because the fan blades recede from the air, creating a void that is quickly filled by air moving toward the blades, driven by a pressure gradient. The airflow near the fan features regions of varying air density, affecting the velocity field of the air particles. As air crosses the fan, it experiences a pressure jump, which accelerates it, although speed changes minimally at this point. Understanding these dynamics requires solving the momentum equation for air with a variable density field.
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My understanding is that when a fan begins spinning, a partial vacuum is created. Physically, what creates this partial vacuum? Does the motion of the blades create a void in which there are fewer air molecules than in the ambient air and thus the pressure is lower than the ambient pressure?
 
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Essentially, yes. The blades of the fan physically push molecules of air out of the way, leaving a partial vacuum behind until more air can move into replace them.
 
Thank you. So a spinning fan creates regions where there are less air molecules than ambient air as well as regions where there are more air molecules than ambient air; I guess this will change the density of the macroscopic air particles near the fan? Does this mean that to determine the velocity field for the macroscopic air particles near a spinning fan, you would need to solve the momentum equation for air particles with a variable density field?
 
The reduced pressure on the intake side of a fan is due to the intake side surfaces of the fan blade receding away from the air. What would be a void left behind by the fan blade is filled in by air accelerating towards the fan blade, but since the air has momentum, it takes a force to produce the acceleration, and the force is due to a pressure gradient where pressure decreases as the air approaches the intake side of a fan. Once the air crosses the fan. there's a jump in pressure, but not much change in speed. The increased pressure causes the air to continue to accelerate, and after the jump in pressure, the pressure decreases with distance from the output side of the fan. An approximation for the speed of the air as it crosses the fan blades is about 1/2 of the air's "exit" speed, which is the speed of the air as it's pressure returns to ambient.

Here is a link to a Nasa article about propeller's showing a similar effect. Note that the decreasing cross section of the affected air in that article is simplified, ignoring the effects of vicosity at the outer edges of the idealized air flow.

http://www.grc.nasa.gov/WWW/K-12/airplane/propanl.html
 
Thank you very much.
 
Hello! Let's say I have a cavity resonant at 10 GHz with a Q factor of 1000. Given the Lorentzian shape of the cavity, I can also drive the cavity at, say 100 MHz. Of course the response will be very very weak, but non-zero given that the Loretzian shape never really reaches zero. I am trying to understand how are the magnetic and electric field distributions of the field at 100 MHz relative to the ones at 10 GHz? In particular, if inside the cavity I have some structure, such as 2 plates...

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