What Determines Electric Field Strengths of Two Charged Rods

AI Thread Summary
The discussion centers on calculating the electric field strengths of two charged rods: a glass rod with a positive charge and a plastic rod with an equal negative charge, positioned 4cm apart. The confusion arises from the initial assumption that the setup resembles a capacitor, which requires conductive materials, while the rods in question are non-conductors. To solve the problem, one must calculate the electric field due to finite line charges and superimpose the fields from both rods. The appropriate formula for this calculation is referenced in a linked document, which provides guidance on determining the electric field from finite line charges. Understanding the distinction between conductors and non-conductors is crucial for correctly approaching this type of problem.
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Homework Statement


The problem I encountered goes like this: A 10cm long thin glass rod uniformly charged to 10nC and a 10cm long thin plastic rod uniformly charged to -10nC are placed side by side 4cm apart. What are the electric field strengths E1 to E3 at distances 1cm, 2cm, and 3cm from the glass rod along the line connecting the midpoints of the two rods?

Homework Equations


E= η/ε0 = (4πK⋅Q) / A

The Attempt at a Solution


I am not quite confused about getting the answer to this problem but as to how I should approach the problem. I thought that the question was describing a capacitor, since the two rods are charged equally but oppositely. But when I tried to use the formula (as shown above), I realized I have no way to find the area. So, I realized that it was not a capacitor. How would I know, aside from looking at the formula, that the question is not describing a capacitor? Or when it describes a capacitor?
 
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To have a capacitor, you need two conductors near one another carrying equal and opposite charges. That's not what you have here because neither glass nor plastic can be considered as conductors. You need to find the electric field due to finite line of charge and superimpose the two fields.
 
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kuruman said:
To have a capacitor, you need two conductors near one another carrying equal and opposite charges. That's not what you have here because neither glass nor plastic can be considered as conductors. You need to find the electric field due to finite line of charge and superimpose the two fields.
Thank you for your explanation. Which formula should I use if I am solving for the electric field due to finite line of charge?
 
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