What Determines the Domain of f(g(x)) for Given Functions?

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The domain of the composite function f(g(x)) where f(x) = sqrt(x-1) and g(x) = x^2 is determined by the conditions of f. Since g(x) is defined for all real numbers, the expression for f(g(x)) becomes sqrt(x^2 - 1). For f(g(x)) to be valid, x^2 must be greater than or equal to 1, leading to the domain being x ≤ -1 or x ≥ 1. Thus, the domain can be expressed as {x | x ≤ -1 ∪ x ≥ 1}.
Coco12
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Let's say f(x) = sqrt(x-1)
And g(x) =x^2

What is the domain of f(g(x))

Well the domain of g(x) is all real numbers and the equation for the new function is sqrt(x^2-1)

Am I right to say that the domain for f(g(x)) is x greater than or equal to 1 and less than and equal to -1??
 
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Coco12 said:
Let's say f(x) = sqrt(x-1)
And g(x) =x^2

What is the domain of f(g(x))

Well the domain of g(x) is all real numbers and the equation for the new function is sqrt(x^2-1)

Am I right to say that the domain for f(g(x)) is x greater than or equal to 1 and less than and equal to -1??
Yes. In a bit nicer form it is ##\{x | x \leq -1 \cup x \geq 1\}##.
 

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