What does it mean for a chemical reaction to do work on a battery?

AI Thread Summary
The voltage rating of a battery is determined by the difference in standard reduction potentials of the materials used in its chemical reactions. Different chemicals have varying abilities to gain or lose electrons, influencing how effectively they can do work on the charges within the battery. A higher voltage, such as that of a 1.5V battery compared to a 1.25V battery, indicates that the materials used undergo redox reactions more readily, resulting in greater energy release. The chemistry of the battery materials directly affects the physics of the voltage produced, as more favorable reactions yield higher voltages. Understanding these principles clarifies how chemical properties translate into electrical performance in batteries.
htttp
Messages
6
Reaction score
0
Hi everyone!

I basically understand how the materials used in the chemical reaction of a battery work but now I want to know why some batteries have different ratings of voltage.

From what I've read, this depends on the materials that are used. What does it mean for some materials to do more work on the charges in the battery? Does this just mean that the chemicals are talking more electrons from the cathode and supplying more electrons for the anode? I guess my real question is what is the difference between a 1.5v battery and a 1.25v battery? I'm not looking for a short answer like "It's just the materials used in the battery." I'm looking for an answer of how those materials affect the charges and how that affects the voltage and how the "chemistry" of the battery affects the "physics" of the battery.

Thanks for all your help!
 
Physics news on Phys.org


I don't know how much chemistry background you have, so if this is either too confusing or not specific enough, please tell me.

Different chemicals (usually metal ions) have different "standard reduction potentials." This basically means that it takes different amounts of energies to add electrons to it, and depend on how strongly electrons in each species are attracted to their nuclei.

[Example table of Standard Reduction Potentials]

If you have a look at the table, you'll see that some species really "like" to gain electrons, while others don't. The more positive they are, the more likely they are to be reduced (gain electrons), while the really negative ones are likely to be oxidised (lose electrons).

A battery basically puts one chemical that oxidises easily on one side, and a chemical that reduces easily on the other. The chemical that oxidises keeps losing electrons, while the chemical that reduces accepts them.

Now, back to that table - the voltage of a battery depends on the difference in standard reduction potential between the chemicals used. Find the two chemicals in a battery on one of those tables and subtract them: the absolute value of that answer is the voltage of your battery.

Basically, the battery's voltage depends on how easily your chosen chemicals oxidise or reduce. If redox reactions happen easily, then the voltage is higher.
 
Last edited by a moderator:
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top