What does it mean to have an integral with a lower bound of infinity?

dmatador
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I am working on a proof in which I have an integral with bounds negative infinity to zero, with an even function, i.e., f(y) = f(-y). I took the limit to infinity rather than negative infinity since y is negative (which is OK I think) but now I have an integral that goes from infinity to 0. What can I make of this? I remember something about this from calculus, but nothing in particular.
 
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dmatador said:
I am working on a proof in which I have an integral with bounds negative infinity to zero, with an even function, i.e., f(y) = f(-y). I took the limit to infinity rather than negative infinity since y is negative (which is OK I think) but now I have an integral that goes from infinity to 0. What can I make of this? I remember something about this from calculus, but nothing in particular.
\int_a^b f(x) dx = -\int_b^a f(x) dx
 
So this holds even when a or b is infinity? If so, thanks for the help. My proof is done.
 
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