What does molarity mean in case of weak electrolytes?

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The discussion centers on the calculation of molarity for a solution containing 5 moles of acetic acid in 1 liter of water. Molarity is defined as the number of moles of solute per total volume of solution. In this case, the formal concentration of acetic acid is 5 M, but the actual molarity of the solution is less than this due to dissociation. The equilibrium concentrations of the components—HAcetate, Acetate-, and H+—are approximately 4.990 M, 9.34×10^-3 M, and 9.34×10^-3 M, respectively, confirming that the total concentration of acetic acid remains at 5 M. However, when considering the final solution's molarity, it is estimated to be around 3.96 M, reflecting the effective concentration after accounting for the volume of the solution.
AnkurGarg
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I am really confused about it.Suppose we add 5 moles of acetic acid in 1 litre of water..The molarity of solution will be -(5 moles)/volume of solution?Or it will be -(the number of moles of acetic acid dissociated/dissolved)/volume of solution
 
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I believe molarity is defined as the number of moles dissolved or otherwise well mixed into solution. Vinegar and water are quite miscible so far I know, so it would be 5 moles/ liter.
 
Molarity of what?

Formal concentration (also called analytical concentration) of acetic acid - 5 M.

Equilibrium concentrations of HAcetate, Acetate-, H+ will be different, you can estimate them to be approximately 4.990 M, 9.34×10-3 M and 9.34×10-3 M respectively. One thing you can be sure about is that [HAcetate] + [Acetate-] = 5 M (this is mass balance of acetic acid).
 
No, molarity always is the quotient of moles per total volume, so 5 moles of acetic acid and one liter of water give a molarity less than 5 moles/l.
 
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Good point.

Assuming 1 L of water and 5 moles of acetic acid final solution would be 3.96 M.
 
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