What does Young's Modulus x 2nd Moment of Area Equal

AI Thread Summary
To determine the relative stiffness of I beams, the product of Young's Modulus and the second moment of area (EI) is essential, as it represents the bending stiffness or flexural rigidity of the beam. The discussion highlights the need for clarity on whether to divide this value by the beam length for accurate calculations. Specific beam dimensions and types are provided, indicating that the user is working with British standard structural steel sections. Additional resources, such as standard tables for the second moment of area, are suggested for precise calculations. Understanding these principles is crucial for analyzing the moment distribution and predicting the force that will cause first yield in the frame.
kiteboy
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Hi all

I need to find the relative stiffnes of certain I beams from here

http://tsbluebook.steel-sci.org/EN/Browsers/Main.htm

Im assuming all I need to do times the Youngs Modulus by the 2nd Moment of Area

In my head I am making it more complicated than it should be so I hope this is all it is

As its all relative units etc don't matter - would that be correct??

Thanks for any info too
 
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Will I also have to divide by the beam length too??
 
Your post is a little vague. Is there a problem associated with your question? It would help if you could post as much information as you can.

In general, the stiffness of a beam in resisting bending is usually determined by its moment of inertia, or the second moment of area. The quantity EI is also called the 'bending stiffness' or the 'flexural rigidity'.
 
There is a problem regarding a frame and the moment distribution method and I need to find the force that that will cause first yield to take place on the fram. It seems a bit involved to put the whole question here so thought Id ask a basic question and the first I think is to get the relative flextural rigidity of the beams of the frames

the beams for example are the following sizes

It is made from structural steel sections of mild steel as follows:
Column AB: universal column section 203x203x60, see section b-b for orientation.
Beam BC: universal beam section 406x178x74, see section a-a for orientation
Column CD: universal column section 254x254x89, see section b-b for orientation

So to start the calcs off and moment distribution the relative stiffness is needed hence me asking the above - sorry if vaugue
 
Apparently, there is some sort of figure associated with this problem. Can you post it?
 
These
kiteboy said:
There is a problem regarding a frame and the moment distribution method and I need to find the force that that will cause first yield to take place on the fram. It seems a bit involved to put the whole question here so thought Id ask a basic question and the first I think is to get the relative flextural rigidity of the beams of the frames

the beams for example are the following sizes

It is made from structural steel sections of mild steel as follows:
Column AB: universal column section 203x203x60, see section b-b for orientation.
Beam BC: universal beam section 406x178x74, see section a-a for orientation
Column CD: universal column section 254x254x89, see section b-b for orientation

So to start the calcs off and moment distribution the relative stiffness is needed hence me asking the above - sorry if vaugue
These are british sections. Do you have standard tables giving you the 2nd M of A for each one?
 
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