What Force Does a Uniform Electric Field Exert on Charge q?

AI Thread Summary
In a uniform electric field, the force exerted on a charge is directly proportional to its magnitude. If the force on a charge 3q is F, then the force on charge q is indeed F/3, as confirmed by the relationship E=F/q. This means that the force experienced by a charge is scaled according to its size in relation to the electric field. The discussion confirms the calculation and understanding of forces in an electric field. The conclusion is that the force on charge q is correctly identified as F/3.
kirby2
Messages
42
Reaction score
0
A charge q and a charge 3q are released in a uniform electric field. If the force this field exerts on 3q is F, the force it will exert on q is:

i think the answer is F/3. is this right? i used E=F/q.
 
Physics news on Phys.org
kirby2 said:
A charge q and a charge 3q are released in a uniform electric field. If the force this field exerts on 3q is F, the force it will exert on q is:

i think the answer is F/3. is this right? i used E=F/q.

Correct.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top