What Force is Needed to Move and Maintain an Ice-Fishing Hut?

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To determine the force needed to move an ice-fishing hut weighing 52N, the initial horizontal force required to start sliding is calculated using the static friction coefficient. Once the hut is in motion, the force needed to maintain a constant speed relies on the kinetic friction coefficient. The mass of the hut is found to be 5.3 kg, but the coefficients of friction are not provided, which complicates the calculations. The equations for static and kinetic friction can be rearranged to express the frictional forces in terms of these coefficients. The discussion highlights the importance of knowing the coefficients of friction to solve the problem accurately.
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Homework Statement



An ice-fishing hut weighing 52N sits on dry, frozen lake.
(a). What is the magnitude of the initial horizontal force required to make the ice-fishing hut start sliding across the surface of the frozen pond?
(b). Once the ice-fishing hut has begun sliding, what force is required to maintain the hut sliding at a constant speed?

Given:
FN: 52N

Homework Equations



Us=Fs/FN

UK=FK/FN

The Attempt at a Solution



I figured out the mass is 5.3 kg by using the formula m=Fg/g and I'm not sure quite what to do next I feel as if some information is lacking? And I'm not quite sure if this question has acceleration and if it does is the acceleration for part (a) is 0?
 
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Sace Ver said:
Us=Fs/FN

UK=FK/FN

Just re-arrange these equations to put the friction force on one side. You are given the normal force, but it looks like you are not given the two coefficients of friction, so just keep them as variables in your answers.
 

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