What Forces Act on a Car at the Peak of a Hill?

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At the peak of a hill, a 1000 kg car traveling at 25 m/s experiences two vertical forces: gravitational force and normal force. To find the net downward force, one must calculate the centripetal force using the car's speed and the hill's radius of curvature of 75 m. The normal force becomes zero when the car reaches the speed necessary to leave the ground, which can be determined through the centripetal force equation. Understanding these forces is essential for analyzing the car's dynamics at the hill's crest. The discussion emphasizes the importance of free body diagrams and applying Newton's laws to solve the problem.
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A 1000 kg car traveling on a road that runs straight up a hill reaches the rounded crest at 25 m/s. If the hill at that point has a radius of curvature of - in a vertical plane - 75 m, what is the net downward force acting on the car at the instant it is horizontal at the very peak? How fast must the car go in order to leave the ground?


Honestly, I'm not even sure how to get started. I'm looking for FN and the car's velocity, but I have no idea what the first step should be. Help please?
 
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pippintook said:
A 1000 kg car traveling on a road that runs straight up a hill reaches the rounded crest at 25 m/s. If the hill at that point has a radius of curvature of - in a vertical plane - 75 m, what is the net downward force acting on the car at the instant it is horizontal at the very peak? How fast must the car go in order to leave the ground?


Honestly, I'm not even sure how to get started. I'm looking for FN and the car's velocity, but I have no idea what the first step should be. Help please?
Part 1: Draw a free body diagram of the car when it is at the top of the crest, and identify the forces acting on it (there are just 2 forces acting in the vertical direction). The net sum of these 2 forces is the centripetal force acting on it. you know v, so just calculate F_centripetal. Part 2: When the car leaves the ground, what is the Normal force acting on it? Then solve for v using the centripetal force equation per Newton 2.
 
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