BobbyJones said:
I have a question that says the velocity of an orbiting satellite is 28620 km/hr. Calculate the height in km of the orbit above the Earth's surface. Gravity is 9.81, and Earth's radius is 6370000. What formulas do I need and how do I work out the height?
Hi Bobby. I'm new to the forums so I hope this response is Kosher. Ok so you have been given a speed for the orbiting satellite, let's call it
Vsat. Ask your self the following two questions:
1. Is Vsat a constant value? (does the speed ever change?)
2. Is the path of the orbit circular in geometry?
If you answer yes to both of the questions, start thinking about uniform circular motion (UCM) and the acceleration associated with that type of motion. Where is the acceleration usually directed for an object subjected to UCM.
Now someone earlier
brilliantly mentioned using netwon's 2nd law of motion; F = ma
Ponder this in regard to the acceleration associated with UCM.
Also think about the type of force that results in the above mentioned acceleration.
Remember we are dealing with a satellite-earth system (one really big particle AND one comparatively smaller particle). These particles are separated by a distance r, where r = radius of Earth + height of satellite above Earth surface.
r = (Re + h)
One last thing. Consider this inverse-square law:
F= G(Mm)/r^2
**where G is a constant
**M is mass 1
**m is mass 2
**r is distance
PM me if you need anymore help.