What formulas do I need and how do I work out the height?

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To calculate the height of an orbiting satellite given its velocity of 28620 km/hr, one must apply Newton's second law and consider the gravitational field strength, which decreases with altitude. The gravitational pull on the satellite can be approximated using the inverse square law, factoring in the Earth's radius of 6370 km. There is a discussion about the validity of the satellite's velocity, as it may be too high for a stable circular orbit. Ultimately, understanding the relationship between gravitational potential energy and kinetic energy is crucial for solving the problem.
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I have a question that says the velocity of an orbiting satellite is 28620 km/hr. Calculate the height in km of the orbit above the Earth's surface. Gravity is 9.81, and Earth's radius is 6370000. What formulas do I need and how do I work out the height?
 
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What force acts on the satellite?
What is the acceleration of the satellite?

Apply Newton's 2nd law.
 
BobbyJones said:
I have a question that says the velocity of an orbiting satellite is 28620 km/hr. Calculate the height in km of the orbit above the Earth's surface. Gravity is 9.81, and Earth's radius is 6370000. What formulas do I need and how do I work out the height?

That 9.81 is the gravitational field strength at the surface, but what is its value up where the satellite is orbiting.

If you knew that you could use the standard expressions for centripetal acceleration.
 
That was all the information I was given on the question. To know the gravitational pull up on the satellite, I need to know the height. So I am stuck.
 
BobbyJones said:
That was all the information I was given on the question. To know the gravitational pull up on the satellite, I need to know the height. So I am stuck.

I didn't say there was a gravitational pull up on the satellite, I was referring to the gravitational field strength when you get up there.

I suppose you could assume it is actually still 9.81 [even though it won't be] and see what you get for R, or you could use the relationship between Gravitational Potential Energy vs kinetic energy of a satellite in stable circular orbit.

This page could contain some useful information and formulae

http://www.sparknotes.com/testprep/books/sat2/physics/chapter11section3.rhtml
 
PeterO said:
I suppose you could assume it is actually still 9.81 [even though it won't be] and see what you get for R
I suspect that it was meant as a generic comment, like use g = 9.81 m/s^2. Of course, it's irrelevant for this particular problem.
 
You may want to verify the given values in the problem statement, the velocity of the satellite in particular. The value looks a bit high to me for a satellite in a circular orbit above the Earth.
 
gneill said:
You may want to verify the given values in the problem statement, the velocity of the satellite in particular. The value looks a bit high to me for a satellite in a circular orbit above the Earth.

? That speed is appropriate for a satellite somewhere between the ISS and Hubble ??

Escape velocity is closer to 40,000 km/hr as I recall. You didn't think the value was given in miles per hour did you?
 
Doc Al said:
I suspect that it was meant as a generic comment, like use g = 9.81 m/s^2. Of course, it's irrelevant for this particular problem.

One could use this value of g and the given radius of the Earth to determine g(r) via the inverse square law.
 
  • #10
gneill said:
One could use this value of g and the given radius of the Earth to determine g(r) via the inverse square law.
That's true. There are many ways to skin the cat.
 
  • #11
gneill said:
You may want to verify the given values in the problem statement, the velocity of the satellite in particular. The value looks a bit high to me for a satellite in a circular orbit above the Earth.
I second that notion. Per my calculations, the satellite is orbiting at an altitude of -71 kilometers.
 
  • #12
BobbyJones said:
I have a question that says the velocity of an orbiting satellite is 28620 km/hr. Calculate the height in km of the orbit above the Earth's surface. Gravity is 9.81, and Earth's radius is 6370000. What formulas do I need and how do I work out the height?

You say the Earth's radius is 6370000. What are the units? If they are km, that is way too large. Always, always state your units.

RGV
 
  • #13
BobbyJones said:
I have a question that says the velocity of an orbiting satellite is 28620 km/hr. Calculate the height in km of the orbit above the Earth's surface. Gravity is 9.81, and Earth's radius is 6370000. What formulas do I need and how do I work out the height?

Hi Bobby. I'm new to the forums so I hope this response is Kosher. Ok so you have been given a speed for the orbiting satellite, let's call it Vsat. Ask your self the following two questions:

1. Is Vsat a constant value? (does the speed ever change?)
2. Is the path of the orbit circular in geometry?

If you answer yes to both of the questions, start thinking about uniform circular motion (UCM) and the acceleration associated with that type of motion. Where is the acceleration usually directed for an object subjected to UCM.

Now someone earlier brilliantly mentioned using netwon's 2nd law of motion; F = ma
Ponder this in regard to the acceleration associated with UCM.

Also think about the type of force that results in the above mentioned acceleration.

Remember we are dealing with a satellite-earth system (one really big particle AND one comparatively smaller particle). These particles are separated by a distance r, where r = radius of Earth + height of satellite above Earth surface.

r = (Re + h)

One last thing. Consider this inverse-square law:

F= G(Mm)/r^2

**where G is a constant
**M is mass 1
**m is mass 2
**r is distance

PM me if you need anymore help.
 
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