What Happens to Surface Charges When a Grounded Wire Connects to a Metal Shell?

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When a grounded wire connects to a metal shell surrounding a charged sphere, the grounding allows free charges to flow to the earth, resulting in a net positive charge on the shell. The grounding ensures the shell maintains zero voltage, indicating that no work is needed to move charges to its surface. This implies that the electric field outside the conductor is zero, leading to the conclusion that the total charge on both the shell and the sphere must also be zero. However, the presence of the charged sphere creates an induced charge on the shell, complicating the situation. Ultimately, the grounding affects the charge distribution and electric field behavior between the sphere and the shell.
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Suppose you've got a metal sphere of radius R and it is surrounded by a metal spherical shell with inner radius r_a and outer radius r_b. The metal sphere has total charge Q. The first thing i had to calculate was what the induced surface charges are on the shell. That was pretty easy, but they then posed the following question.

Suppose you'd connect a wire to the spherical shell that is connected to the earth. What happens to the surface charges of this shell.

I thought because of the grounding wire, all the free charges float to the earth, leaving the shell positively charged. But you've also got the attraction of the sphere at the center. So basically i don't have a clue what happens :smile:

Can anybody give some hints? :smile:
 
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Connecting a conductor to groud gives it a zero voltage. In other words, it would take no work to move a charge from very far away to the surface of the outer conductor after connecting the wire. What does this say about the field outside the conductor and the total charge on both?
 
Since E is the gradient of the potential, it would mean the total electric field is zero. Then according to gauss's law the total charge would be zero also. So this would mean the electric field of the sphere doesn't create a induced charge on the shell and is also non-zero in the region between the sphere and the shell. Right?
 
No, because then there would be a field outside the sphere/shell assembly. There has to be zero total charge on all conductors.
 
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