What happens to the pressure and byproducts in a contained hydrogen explosion?

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In a contained hydrogen explosion, the initial ignition causes a rapid spike in pressure due to the combustion of hydrogen and oxygen, producing water vapor as the primary byproduct. As the reaction occurs, the volume of gas decreases significantly because water is much more compressed than the gaseous reactants. If the temperature exceeds 374.1°C, the water remains in a vapor state despite the pressure changes. Conversely, if the temperature is below the critical point, maintaining the temperature while managing pressure can lead to condensation. Ultimately, the dynamics of pressure and temperature dictate the state of water and any potential byproducts in the container.
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This is an interesting thing to me, imagine a spherical container filled with a perfect hydrogen to oxygen fuel air mixture, there is an ignition source(such as a spark plug) in the container. So you light off the gasses, what happens to the pressure in the container? My resoning says obviously it spikes immediately, but then what happens, water is much more compressed than the gasses, so you've burned the hydrogen, and water is your result, because of the compression factor of the gasses into water, would it pull a vacuum on the container? and if it did, would it boil the water and keep it in a vapor state? are there any other byproducts in the container?
 
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My spidey senses say there will be a pressure/heat spike and then the water will stay vapourised simply because it can in the resulting low pressure environment. No other byproducts.
 
that depend upon temperature
if t>374.1 C
water will remain in vapor state. irrespective of spike in pressure
on the other hand if t< critical t
and you maintain the temperature by any hypothetical process
and p> needed for condensation at t
volume of gas=\frac{v_{g}-v}{v_{g}-v_{l}}
if 1 mole of water is present
where v_{g},v_{l},are molar vol.
 
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