What Happens to the Speed and Proximity of Two Charged Metal Spheres in Motion?

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The discussion revolves around a physics problem involving two charged metal spheres, where one sphere is stationary and the other is projected towards it. The key focus is on calculating the speed of the moving sphere when the distance between them decreases and determining how close it gets to the stationary sphere. The user attempted to apply conservation of energy principles, using equations related to kinetic and potential energy, but encountered difficulties in their calculations of electrical potential. They specifically questioned the accuracy of their voltage calculations and sought clarification on the electrical potential energy between point charges. The conversation emphasizes the importance of correctly applying energy conservation in electrostatics to solve the problem.
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Homework Statement


A small metal sphere, carrying a net charge of q_1 = -2.60 \mu C, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q_2 = -7.70 \mu C and mass 1.40 g, is projected toward q_{1}. When the two spheres are 0.800 \rm m apart, q_{2} is moving toward q_{1} with speed 22.0 \rm m/s . Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.
What is the speed of q_{2} when the spheres are 0.450 m apart
?How close does q_{2} get to q_{1}?


Homework Equations


Ka+Ua=Kb+Ub
U=qv
V=k(q1/r)




The Attempt at a Solution


I figured this was a simple conservation of energy problem, so i began it at such.
.5m2Vi^2 + q2Va = .5m2Vf^2 + q2Vb

after simplifying it all down i got:
sqrt((m2vi^2 + q2(Va-Vb))/m2) = Vf

I calculated Va to be -29233V and Vb to be -51952V. I am not sure what i did wrong here.
to calculate V i used q1, the charge of motionless sphere, since V is independent of the observer charge. For the r i used the distance from the moving sphere to sphere, and i used both values. when multiplying (Va-Vb) by q i used the q value of the moving sphere. Please help!
 
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